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  • HDU 5772 String problem

    最大权闭合子图。建图巧妙。

    最大权闭合子图:

    #pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<cstdio>
    #include<cstring>
    #include<cmath>
    #include<algorithm>
    #include<vector>
    #include<map>
    #include<set>
    #include<queue>
    #include<stack>
    #include<iostream>
    using namespace std;
    typedef long long LL;
    const double pi=acos(-1.0),eps=1e-8;
    void File()
    {
        freopen("D:\in.txt","r",stdin);
        freopen("D:\out.txt","w",stdout);
    }
    inline int read()
    {
        char c = getchar();  while(!isdigit(c)) c = getchar();
        int x = 0;
        while(isdigit(c)) { x = x * 10 + c - '0'; c = getchar(); }
        return x;
    }
    
    const int maxn = 30000 + 10;
    const int INF = 0x7FFFFFFF;
    struct Edge
    {
        int from, to, cap, flow;
        Edge(int u, int v, int c, int f) :from(u), to(v), cap(c), flow(f) {}
    };
    vector<Edge>edges;
    vector<int>G[maxn];
    bool vis[maxn];
    int d[maxn];
    int cur[maxn];
    int n, m, s, t;
    
    void init()
    {
        for (int i = 0; i < maxn; i++) G[i].clear();
        edges.clear();
    }
    void AddEdge(int from, int to, int cap)
    {
        edges.push_back(Edge(from, to, cap, 0));
        edges.push_back(Edge(to, from, 0, 0));
        int w = edges.size();
        G[from].push_back(w - 2);
        G[to].push_back(w - 1);
    }
    bool BFS()
    {
        memset(vis, 0, sizeof(vis));
        queue<int>Q;
        Q.push(s);
        d[s] = 0;
        vis[s] = 1;
        while (!Q.empty())
        {
            int x = Q.front();
            Q.pop();
            for (int i = 0; i<G[x].size(); i++)
            {
                Edge e = edges[G[x][i]];
                if (!vis[e.to] && e.cap>e.flow)
                {
                    vis[e.to] = 1;
                    d[e.to] = d[x] + 1;
                    Q.push(e.to);
                }
            }
        }
        return vis[t];
    }
    int DFS(int x, int a)
    {
        if (x == t || a == 0)
            return a;
        int flow = 0, f;
        for (int &i = cur[x]; i<G[x].size(); i++)
        {
            Edge e = edges[G[x][i]];
            if (d[x]+1 == d[e.to]&&(f=DFS(e.to,min(a,e.cap-e.flow)))>0)
            {
                edges[G[x][i]].flow+=f;
                edges[G[x][i] ^ 1].flow-=f;
                flow+=f;
                a-=f;
                if(a==0) break;
            }
        }
        if(!flow) d[x] = -1;
        return flow;
    }
    int dinic(int s, int t)
    {
        int flow = 0;
        while (BFS())
        {
            memset(cur, 0, sizeof(cur));
            flow += DFS(s, INF);
        }
        return flow;
    }
    
    const int MAXM=110;
    int T,len,a[MAXM],b[MAXM],w[MAXM][MAXM],val[2*MAXM*MAXM],ans;
    char str[MAXM];
    
    int main()
    {
        scanf("%d",&T); int cas=1;
        while(T--)
        {
            scanf("%d",&len); scanf("%s",str);
            for(int i=0;i<10;i++) scanf("%d%d",&a[i],&b[i]);
            for(int i=0;i<len;i++) for(int j=0;j<len;j++) scanf("%d",&w[i][j]);
    
            init(); ans=0;
            s=len*len+len+10; val[s]=0;
            t=len*len+len+10+1; val[t]=0;
    
            for(int i=0;i<len;i++) for(int j=i+1;j<len;j++)
            {
                val[i*len+j]=w[i][j]+w[j][i];
                AddEdge(i*len+j,len*len+i,INF);
                AddEdge(i*len+j,len*len+j,INF);
                if(val[i*len+j]>0) AddEdge(s,i*len+j,val[i*len+j]), ans=ans+val[i*len+j];
                else if(val[i*len+j]<0) AddEdge(i*len+j,t,-val[i*len+j]);
            }
            for(int i=len*len;i<=len*len+len-1;i++)
            {
                val[i]=-a[str[i-len*len]-'0'];
                AddEdge(i,len*len+len+str[i-len*len]-'0',INF);
                if(val[i]>0) AddEdge(s,i,val[i]), ans=ans+val[i];
                else if(val[i]<0) AddEdge(i,t,-val[i]);
            }
            for(int i=len*len+len;i<=len*len+len+10-1;i++)
            {
                val[i]=-b[i-(len*len+len)]+a[i-(len*len+len)];
                if(val[i]>0) AddEdge(s,i,val[i]), ans=ans+val[i];
                else if(val[i]<0) AddEdge(i,t,-val[i]);
            }
            ans=ans-dinic(s,t);
            printf("Case #%d: %d
    ",cas++,ans);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zufezzt/p/5722351.html
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