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  • HDU 5880 Family View

    $AC$自动机。

    用$AC$自动机匹配一次,开一个$flag$记录一下以$i$位置为结尾的最长要打$*$多少个字符,然后倒着扫描一次就可以输出了。

    #pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<cstdio>
    #include<cstring>
    #include<cmath>
    #include<algorithm>
    #include<vector>
    #include<map>
    #include<set>
    #include<queue>
    #include<stack>
    #include<bitset>
    #include<iostream>
    using namespace std;
    typedef long long LL;
    const double pi=acos(-1.0),eps=1e-6;
    void File()
    {
        freopen("D:\in.txt","r",stdin);
        freopen("D:\out.txt","w",stdout);
    }
    template <class T>
    inline void read(T &x)
    {
        char c=getchar(); x=0;
        while(!isdigit(c)) c=getchar();
        while(isdigit(c)) {x=x*10+c-'0'; c=getchar();}
    }
    
    const int maxn=1000010;
    int flag[maxn];
    char buf[maxn];
    
    struct Trie
    {
        int next[maxn][26],fail[maxn],end[maxn],Len[maxn];
        int root,L;
        int newnode()
        {
            for(int i = 0;i < 26;i++) next[L][i] = -1;
            Len[L]= end[L] = 0; L++;
            return L-1;
        }
        void init()
        {
            L = 0;
            root = newnode();
        }
        void insert(char buf[])
        {
            int len = strlen(buf);
            int now = root;
            for(int i = 0;i < len;i++)
            {
                if(next[now][buf[i]-'a'] == -1)
                    next[now][buf[i]-'a'] = newnode();
                now = next[now][buf[i]-'a'];
            }
            end[now]++;
            Len[now]=strlen(buf);
        }
        void build()
        {
            queue<int>Q;
            fail[root] = root;
            for(int i = 0;i < 26;i++)
                if(next[root][i] == -1)
                    next[root][i] = root;
                else
                {
                    fail[next[root][i]] = root;
                    Q.push(next[root][i]);
                }
            while( !Q.empty() )
            {
                int now = Q.front();
                Q.pop();
                for(int i = 0;i < 26;i++)
                    if(next[now][i] == -1)
                        next[now][i] = next[fail[now]][i];
                    else
                    {
                        fail[next[now][i]]=next[fail[now]][i];
                        Q.push(next[now][i]);
                    }
            }
        }
        void query(char buf[])
        {
            int len = strlen(buf);
            int now = root;
            int res = 0;
            for(int i = 0;i < len;i++)
            {
                int sign;
                if(buf[i]>='A'&&buf[i]<='Z') sign=buf[i]-'A';
                else if(buf[i]>='a'&&buf[i]<='z') sign=buf[i]-'a';
                else { now=root; continue; }
                now = next[now][sign];
                int temp = now;
                while( temp != root )
                {
                    flag[i]=max(flag[i],Len[temp]);
                    temp = fail[temp];
                }
            }
        }
    };
    
    Trie ac;
    
    int main()
    {
        int T,n; scanf("%d",&T);
        while( T-- )
        {
            scanf("%d",&n); ac.init();
            for(int i = 0;i < n;i++)
                { scanf("%s",buf); ac.insert(buf); }
            ac.build();
    
            getchar(); gets(buf); memset(flag,0,sizeof flag);
            ac.query(buf);
    
            int leng=strlen(buf); int num=0;
    
            for(int i=leng-1;i>=0;i--)
            {
                num=max(num,flag[i]);
                if(num==0) continue;
                else buf[i]='*', num--;
            }
            printf("%s
    ",buf);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zufezzt/p/5893981.html
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