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  • BZOJ2388: 旅行规划(分块 凸包)

    题意

    题目链接

    Sol

    直接挂队爷的题解了

    分块题好难调啊qwq

    #include<bits/stdc++.h>
    #define LL long long 
    using namespace std;
    const int MAXN = 1e6 + 10;
    const LL INF = 6e18;
    template <typename A, typename B> inline bool chmin(A &a, B b){if(a > b) {a = b; return 1;} return 0;}
    template <typename A, typename B> inline bool chmax(A &a, B b){if(a < b) {a = b; return 1;} return 0;}
    inline int read() {
        char c = getchar(); int x = 0, f = 1;
        while(c < '0' || c > '9') {if(c == '-') f = -1; c = getchar();}
        while(c >= '0' && c <= '9') x = x * 10 + c - '0', c = getchar();
        return x * f;
    }
    int N, M, block, bel[MAXN], bl[MAXN], br[MAXN], mx;
    vector<int> con[MAXN];
    LL bg[MAXN], d[MAXN], a[MAXN];
    double slope(int x, int y) {
        return double (a[y] - a[x]) / (y - x);
    }
    void rebuild(int id) {
        vector<int> &v = con[id]; v.clear();
        for(int i = bl[id]; i <= br[id]; i++) {
            while(v.size() > 1 && (slope(v[v.size() - 2], i) >= (slope(v[v.size() - 2], v[v.size() - 1])))) v.pop_back();   
            v.push_back(i);
        }
    }
    LL Find(vector<int> &v, double k, int lef) {
        int l = 0, r = v.size() - 1, ans = 0;
        while(l <= r) {
            int mid = l + r >> 1;
            if(mid == 0 || (slope(v[mid - 1], v[mid]) > k)) ans = mid, l = mid + 1;
            else r = mid - 1;
        }
        return a[v[ans]] + 1ll * (v[ans] - lef + 1) * (-k);
    }
    void Modify(int l, int r, int val) {
        for(int i = l; i <= min(r, br[bel[l]]); i++) a[i] += 1ll * val * (i - l + 1);
        rebuild(bel[l]);
        if(bel[l] != bel[r]) {
            for(int i = bl[bel[r]]; i <= r; i++) a[i] += 1ll * val * (i - l + 1);
        }
        for(int i = r + 1; i <= br[bel[r]]; i++) a[i] += 1ll * val * (r - l + 1);
        rebuild(bel[r]);
        for(int i = bel[l] + 1; i <= bel[r] - 1; i++) {
            bg[i] += 1ll * (bl[i] - l + 1) * val - val;
            d[i]  += val;
        }
        for(int i = bel[r] + 1; i <= mx; i++) bg[i] += 1ll * val * (r - l + 1);
    }
    LL Query(int l, int r) {
        LL ans = -INF;
        for(int i = l; i <= min(r, br[bel[l]]); i++)
            chmax(ans, bg[bel[l]] + 1ll * (i - bl[bel[l]] + 1) * d[bel[l]] + a[i]);
        if(bel[l] != bel[r]) {
            for(int i = bl[bel[r]]; i <= r; i++) 
                chmax(ans, bg[bel[r]] + 1ll * (i - bl[bel[r]] + 1) * d[bel[r]] + a[i]);
        }
        for(int i = bel[l] + 1; i <= bel[r] - 1; i++) {
            chmax(ans, bg[i] + Find(con[i], -d[i], bl[i]));
        }
        return ans;
    }
    signed main() {
        N = read();  block = sqrt(N);
        for(int i = 1; i <= N; i++) a[i] = read() + a[i - 1], bel[i] = (i - 1) / block + 1, chmax(mx, bel[i]);
    //  for(int i = 1; i <= 16; i++) cout << a[i] << " ";
        for(int i = 1; i <= mx; i++)  bl[i] = (i - 1) * block + 1, br[i] = bl[i] + block - 1, rebuild(i);
        M = read();
        for(int i = 1; i <= M; i++) {
            int opt = read();
            if(opt == 0) {
                int l = read(), r = read(), v = read();
                Modify(l, r, v);
            } else {
                int l = read(), r = read();
                cout << Query(l, r) << '
    ';
            }
        }
        return 0;
    }
    /*
    16
    51 -6867 25916 -19111 -23413 -282 7274 6888 15114 6563 18264 -11811 27336 14638 19495 -10931
    1
    1 9 16
    
    */
    
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  • 原文地址:https://www.cnblogs.com/zwfymqz/p/10270098.html
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