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  • loj#2312. 「HAOI2017」八纵八横(线性基 线段树分治)

    题意

    题目链接

    Sol

    线性基+线段树分治板子题。。

    调起来有点自闭。。

    #include<bits/stdc++.h> 
    #define fi first
    #define se second
    #define pb push_back 
    #define bit bitset<B + 1> 
    using namespace std;
    const int MAXN = 501,  B = 1001, SS = 4001;
    inline int read() {
        char c = getchar(); int x = 0, f = 1;
        while(c < '0' || c > '9') {if(c == '-') f = -1; c = getchar();}
        while(c >= '0' && c <= '9') x = x * 10 + c - '0', c = getchar();
        return x * f;
    }
    int N, M, Q, las[SS];
    struct Graph {
    	struct Edge {
    		int u, v;
    		bit w;
    		int nxt;
    	}E[3021];
    	int head[MAXN], num, vis[MAXN];
    	Graph() {
    		memset(head, -1, sizeof(head));
    		memset(vis, 0, sizeof(vis));
    		num = 0;
    	}
    	bit P[B + 1], dis[MAXN];
    	void insert(bit s) {
    		for(int i = B; ~i; i--) {
    			if(s[i]) {
    				if(!P[i].count()) {P[i] = s; break;}
    				s = s ^ P[i];
    			}
    		}
    	}
    	void dfs(int x, int fa) {
    		vis[x] = 1;
    		for(int i = head[x]; ~i; i = E[i].nxt) {
    			int to = E[i].v; bit w = E[i].w;
    			if((i ^ 1) == fa) continue;
    			if(vis[to]) insert(dis[x] ^ dis[to] ^  w);
    			else {
    				dis[to] = dis[x] ^ w; 
    				dfs(to, i);
    			}
    		}
    	}
    	void Query() {
    		bit ans; ans.reset();
    		for(int i = B; ~i; i--) if(ans[i] ^ (P[i][i])) ans ^= P[i];
    		for(int i = B; ~i; i--) 
    			if(ans[i]) {
    				for(int j = i; ~j; j--) cout << ans[j];
    				puts("");
    				return ;
    			}	
    		puts("0");
    	}
    	void AddEdge(int x, int y, bit w) {
    		E[num] = {x, y, w, head[x]};
    		head[x] =num++;
    	}
    	void Insert(int x, int y, bit w) {
    		insert(dis[x] ^ dis[y] ^ w);
    	}
    
    }bg;
    struct Edge {
    	int u, v;
    	bit w;
    }e[SS];
    vector<Edge> tag[SS];
    
    #define ls k << 1
    #define rs k << 1 | 1
    void Add(int k, int l, int r, int ql, int qr, Edge v) {
    	if(ql > qr) return ;
    	if(ql <= l && r <= qr) {tag[k].pb(v); return ;}
    	int mid = l + r >> 1;
    	if(ql <= mid) Add(ls, l, mid, ql, qr, v);
    	if(qr  > mid) Add(rs, mid + 1, r, ql, qr, v);
    }
    void Down(int k, int l, int r, Graph now) {
    	if(l > r) return ;
    	Graph nxt = now;
    	for(auto flag: tag[k]) 
    		nxt.Insert(flag.u, flag.v, flag.w);
    	if(l == r) {
    		nxt.Query(); 
    		return ;
    	}
    	int mid = l + r >> 1;
    	Down(ls, l, mid, nxt);
    	Down(rs, mid + 1, r, nxt);
    }
    signed main() {
    	N = read(); M = read(); Q = read();
    	for(int i = 1; i <= M; i++) {
    		int x = read(), y = read(); bit w; cin >> w;
    		bg.AddEdge(x, y, w);
    		bg.AddEdge(y, x, w);
    	}
    	memset(las, -1, sizeof(las));
    	int youducuotile = 0;
    	for(int i = 1; i <= Q; i++) {
    		char opt[10]; scanf("%s", opt + 1);
    		if(opt[1] == 'A') {
    			e[++youducuotile ].u = read(), e[youducuotile ].v = read();
    			cin >> e[youducuotile ].w; las[youducuotile ] = i;
    		} else if(opt[1] == 'C' && opt[2] == 'a') {
    			int k = read(); 
    			Add(1, 1, Q, las[k], i - 1, e[k]); 
    			las[k] = -1;
    		} else {
    			int k = read();
    			Add(1, 1, Q, las[k], i - 1, e[k]);
    			cin >> e[k].w;
    			las[k] = i;
    		}
    	}
    	for(int i = 1; i <= Q; i++)
    		if(~las[i])
    			Add(1, 1, Q, las[i], Q, e[i]);
    	bg.dfs(1, -1);
    	bg.Query();
    	if(Q) 
    		Down(1, 1, Q, bg);
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/zwfymqz/p/10628619.html
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