UVA 11346

Consider rectangular coordinate system and point L(X, Y ) which is randomly chosen among all points
in the area A which is defined in the following manner: A = {(x, y)|x ∈ [−a; a];y ∈ [−b; b]}. What is
the probability P that the area of a rectangle that is defined by points (0,0) and (X, Y ) will be greater
than S?
Input
The number of tests N ≤ 200 is given on the first line of input. Then N lines with one test case on
each line follow. The test consists of 3 real numbers a > 0, b > 0 ir S ≥ 0.
Output
For each test case you should output one number P and percentage ‘%’ symbol following that number
on a single line. P must be rounded to 6 digits after decimal point.
Sample Input
3
10 5 20
1 1 1
2 2 0
Sample Output
23.348371%
0.000000%
100.000000%

题解：给你x，y，s，问说在x,y与x,y轴形成的矩形内选取一点，和x，y轴形成图形的面积大于s的概率。

题解： 

 　　　　　　画个图是求个积分

　　　　　　S = s* (ln(x1)- ln(x));

#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstring>
#include <algorithm>
#include <vector>
#include <bitset>
using namespace std ;
typedef long long ll;

const int N = 3000 + 5;


int main () {
    int T;
    scanf("%d",&T);
    while(T--) {
            double x,y,s;
        scanf("%lf%lf%lf",&x,&y,&s);
        double x1 = min(x,s / y);
        double S = 0;
        if(s > 1e-9) S = x1 * y + s * (log(x) - log(x1));
        //cout<<S<<endl;
        double p = 1.0 - S / (x * y);
        p *= 100;
        printf("%.6f%%
", p);
    }
    return 0;
}