Java switch 中如何使用枚举？

enum HobbyEnum{
SIGN("唱","SING"),
JUMP("跳","JUMP"),
RAP("Rap","RAP"),
OTHER("未知","OTHER");

private String word;
private String type;

HobbyEnum(String word, String type){
this.word = word;
this.type = type;
}

public String getWord() {
return word;
}

public void setWord(String word) {
this.word = word;
}

public String getType() {
return type;
}

public void setType(String type) {
this.type = type;
}

public static HobbyEnum getByType(String type){
for (HobbyEnum constants : values()) {
if (constants.getType().equalsIgnoreCase(type)) {
return constants;
}
}
return OTHER;
}
}

想使用switch去替换掉if-else，想到Hobby这个类里面的type属性正好是个枚举，就想用枚举去实现，结果发现这样是有问题的。

枚举类

public enum HobbyEnum{
SIGN("唱","SING"),
JUMP("跳","JUMP"),
RAP("Rap","RAP"),
OTHER("未知","OTHER");

private String word;
private String type;

HobbyEnum(String word, String type){
this.word = word;
this.type = type;
}

public String getWord() {
return word;
}

public void setWord(String word) {
this.word = word;
}

public String getType() {
return type;
}

public void setType(String type) {
this.type = type;
}
}

解决方案

修改枚举类

新增一个静态方法，getByType()

enum HobbyEnum{
SIGN("唱","SING"),
JUMP("跳","JUMP"),
RAP("Rap","RAP"),
OTHER("未知","OTHER");

private String word;
private String type;

HobbyEnum(String word, String type){
this.word = word;
this.type = type;
}

public String getWord() {
return word;
}

public void setWord(String word) {
this.word = word;
}

public String getType() {
return type;
}

public void setType(String type) {
this.type = type;
}

public static HobbyEnum getByType(String type){
for (HobbyEnum constants : values()) {
if (constants.getType().equalsIgnoreCase(type)) {
return constants;
}
}
return OTHER;
}
}

转载至 https://www.cnblogs.com/codeclock/p/12564924.html