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  • HDU

    就是阶梯NIM博弈,那么看层数是不是奇数的异或就行了;

    #include<iostream>
    #include<cstdio>
    #include<algorithm>
    #include<cstdlib>
    #include<cstring>
    #include<string>
    #include<cmath>
    #include<map>
    #include<set>
    #include<vector>
    #include<queue>
    #include<bitset>
    #include<ctime>
    #include<deque>
    #include<stack>
    #include<functional>
    #include<sstream>
    //#include<cctype>
    //#pragma GCC optimize(2)
    using namespace std;
    #define maxn 400005
    #define inf 0x7fffffff
    //#define INF 1e18
    #define rdint(x) scanf("%d",&x)
    #define rdllt(x) scanf("%lld",&x)
    #define rdult(x) scanf("%lu",&x)
    #define rdlf(x) scanf("%lf",&x)
    #define rdstr(x) scanf("%s",x)
    typedef long long  ll;
    typedef unsigned long long ull;
    typedef unsigned int U;
    #define ms(x) memset((x),0,sizeof(x))
    const long long int mod = 1e9;
    #define Mod 1000000000
    #define sq(x) (x)*(x)
    #define eps 1e-11
    typedef pair<int, int> pii;
    #define pi acos(-1.0)
    //const int N = 1005;
    #define REP(i,n) for(int i=0;i<(n);i++)
    typedef pair<int, int> pii;
    
    inline int rd() {
    	int x = 0;
    	char c = getchar();
    	bool f = false;
    	while (!isdigit(c)) {
    		if (c == '-') f = true;
    		c = getchar();
    	}
    	while (isdigit(c)) {
    		x = (x << 1) + (x << 3) + (c ^ 48);
    		c = getchar();
    	}
    	return f ? -x : x;
    }
    
    
    ll gcd(ll a, ll b) {
    	return b == 0 ? a : gcd(b, a%b);
    }
    int sqr(int x) { return x * x; }
    
    
    
    /*ll ans;
    ll exgcd(ll a, ll b, ll &x, ll &y) {
    	if (!b) {
    		x = 1; y = 0; return a;
    	}
    	ans = exgcd(b, a%b, x, y);
    	ll t = x; x = y; y = t - a / b * y;
    	return ans;
    }
    */
    int T;
    vector<int>vc[maxn];
    int ans;
    int a[maxn];
    void dfs(int u,int fa,int dep){
    	for(int i=0;i<vc[u].size();i++){
    		int v=vc[u][i];
    		if((dep+1)%2)ans^=a[v];
    		dfs(v,u,dep+1);
    	}
    }
    int main() {
    	T=rd();
    	while(T--){
    		int n;rdint(n);
    		for(int i=0;i<=n;i++)vc[i].clear();
    		for(int i=1;i<n;i++){
    			int fa;rdint(fa);
    			vc[fa].push_back(i);
    		}
    		ans=0;
    		for(int i=0;i<n;i++)rdint(a[i]);
    		dfs(0,0,0);
    		if(ans)cout<<"win"<<endl;
    		else cout<<"lose"<<endl;
    	}
    }
    
    EPFL - Fighting
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  • 原文地址:https://www.cnblogs.com/zxyqzy/p/10344345.html
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