一般情况下Pivot()函数中in中只能写死，因为PIVOT()的in中不支持子查询，所以这样的话只能用存储过程来解决；
CREATE PROCEDURE InsurancePivot
@Foldercode VARCHAR(50),
@isY VARCHAR(4)
AS
BEGIN DECLARE @ColumnNames VARCHAR(3000)
SET @ColumnNames=''
SELECT @ColumnNames = @ColumnNames + '[' + TESTNO + '],'
FROM ( SELECT TESTNO FROM ORDTASK
LEFT JOIN TESTS ON TESTS.TESTCODE = ORDTASK.TESTCODE
WHERE ORDTASK.FOLDERNO IN (SELECT FOLDERNO FROM FOLDERS WHERE FOLDERCODE = @Foldercode) ) t
SET @ColumnNames= LEFT(@ColumnNames, LEN(@ColumnNames)-1)
DECLARE @selectSQL NVARCHAR(3000)
SET @selectSQL= 'SELECT P.* FROM ( select foldercode as "受理单编号",ordcode as "样品编号",orders.ORIGINALNO as "原始编号", orders.name as "姓名", pa.SEX as "性别", pa.AGE as "年龄", pa.ADDRESS as "现住址", folders.DATERECV as "收样日期",FINAL,name.TESTCODE, orders.SAMPLINGDATE, TESTNO
from orders left join folders on orders.folderno = folders.folderno
left join PATIENTS pa on pa.PID = orders.PID
left join (select ordno, results.FINAL,tests.testno ,tests.testcode
from analytes
left join ORDTASK on ordtask.TESTCODE = analytes.TESTCODE and ordtask.METHOD = analytes.METHOD
left join results on results.ANALYTE = analytes.ANALYTE and results.ORDTASKNO = ordtask.ORDTASKNO
left join tests on tests.testcode = analytes.TESTCODE
where analytes.displayflag = '''+@isY+''') name on name.ordno = orders.ordno where foldercode = '''+@Foldercode+''' ) a
pivot( max(FINAL) for TESTNO in ({0}))p'
SET @selectSQL= REPLACE(@selectSQL,'{0}',@ColumnNames)
EXEC sp_executesql @selectSQL
END
GO