杭电2054：A == B ?

Problem Description

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

 

Input

each test case contains two numbers A and B.

 

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

 

Sample Input

1

22

23

34

3

 

Sample Output

NO

YES

YES

NO

这道题题意简单，判断A和B是否相等，但是A和B不能直接比较，前补0要去掉，小数点后末尾0也要去掉。

#include<stdio.h>
#include<string.h>
#define N 100020
char a[N],b[N];
int main()
{
    int i,j,l1,l2,l3,l4,len1,len2;
    while(scanf("%s%s",a,b)!=EOF)
    {
        len1=strlen(a);
        len2=strlen(b);
        len1--;
        len2--;
        for(i=0;i<=len1;i++)
            if(a[i]!='0')
                break;
        l1=i;
        l2=len1;
        for(j=len1;j>=0;j--)
        {
            if(a[j]=='.')
            {
                for(i=len1;i>=l1;i--)
                {
                	if(a[i]=='.')
                    {
                        i--;
                        break;
                    } 
                    if(a[i]!='0')
                        break;
                    
                }
                l2=i;
                break;
            }
        }
        
            
        
        for(i=0;i<=len2;i++)
        {
            if(b[i]!='0')
                break;
        }
            
        l3=i;
        l4=len2;
        for(j=len2;j>=0;j--)
        {
            if(b[j]=='.')
            {
                for(i=len2;i>=l3;i--)
                {
                	if(b[i]=='.')
                    {
                        i--;
                        break;
                    }
                    if(b[i]!='0')
                        break;
                    
                }
                l4=i;
                break;    
            }
        }
        
        int temp=1;
        i=l1;j=l3;
        
        for(;i<=l2&&j<=l4;)
        {
            if(a[i]!=b[j])
            {
                temp=0;
                break;
            }
            i++;j++;
        }
        if(i!=l2+1||j!=l4+1)
            temp=0;
        if(temp==1)
            printf("YES
");
        else
            printf("NO
");
    }
    return 0;
}