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  • 链表分段反转

    public class Node {
        //定义Node节点
        static class ListNode {
            public int val;
            public ListNode next = null;
    
            public ListNode(int val) {
                this.val = val;
            }
        }
    
        public static void main(String[] args) {
            //1.获取输入信息
            Scanner scanner = new Scanner(System.in);
            String string = scanner.nextLine();
            int k = scanner.nextInt();
            String[] strings = string.split(" ");
            //2.创建头结点
            ListNode head = new ListNode(0);
            ListNode tail = head;
            //3.将输入的字符串变为链表节点
            for (String str : strings) {
                ListNode newNode = new ListNode(Integer.valueOf(str));
                tail.next = newNode;
                tail = tail.next;
            }
            head = head.next;
            //每k个反转链表
            ListNode node = reverseGroup(head, k);
            while(node!=null){
                System.out.print(node.val+" ");
                node = node.next;
            }
        }
    
        //不停地取k个进行翻转,如果不够k个,就直接返回,结束
        public static ListNode reverseGroup(ListNode head, int k) {
            if (head == null || head.next == null || k <= 1)
                return head;
            ListNode currentNode = head;
            //获取k个元素的首尾节点
            for (int count = 1; count < k; count++) {
                currentNode = currentNode.next;
                //不够K个则返回
                if(currentNode==null)
                    return head;
            }
            ListNode next = currentNode.next;
            //对局部链表进行反转
            reverse(head,currentNode);
            head.next=reverseGroup(next,k);
            return currentNode;
        }
    
        //写一个头尾节点反转的局部函数
        public static ListNode reverse(ListNode head, ListNode tail) {
            if (head == null || head.next == null)
                return head;
            ListNode pre = null;
            ListNode next = null;
            while (pre != tail) {
                next = head.next;
                head.next = pre;
                pre = head;
                head = next;
            }
            return pre;
        }
    }
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  • 原文地址:https://www.cnblogs.com/zzq-include/p/13384831.html
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