【Java】【集合类】Java 中初始化 List 集合的方式

 

List 是在开发中比较常用的集合，今天总结一下 Java 中初始化 List 的几种方式。

1、常规方式

List<String> list = new ArrayList<>();
list.add("1");
list.add("2");
list.add("3");
System.out.println("getList1: " + list);

输出

getList1: [1, 2, 3]

2、Arrays 工具类

// 生成的list不可变
List<String> list = Arrays.asList("1", "2", "3");
System.out.println("getList2: " + list);
// 如果要可变需要用ArrayList包装一下
List<String> numbers = new ArrayList<>(Arrays.asList("1", "2", "3"));
numbers.add("4");
System.out.println("numbers: " + numbers);

输出

getList2: [1, 2, 3]
numbers: [1, 2, 3, 4]

3、Collections 工具类

// 生成的list不可变
List<String> list = Collections.nCopies(3, "1");
System.out.println("getList3: " + list);
// 如果要可变需要用ArrayList包装一下
List<String> dogs = new ArrayList<>(Collections.nCopies(3, "dog"));
dogs.add("dog");
System.out.println("dogs: " + dogs);

输出

getList3: [1, 1, 1]
dogs: [dog, dog, dog, dog]

4、Lists 工具类

List<String> list = Lists.newArrayList("1", "2", "3");
System.out.println("getList4: " + list);

输出

getList4: [1, 2, 3]

5、匿名内部类

List<String> list = new ArrayList<String>() {{
     add("1");
     add("2");
     add("3");
}};
System.out.println("getList5: " + list);

输出

getList5: [1, 2, 3]

6、ImmutableList

List<String> list = ImmutableList.of("1", "2", "3");
System.out.println("getList6: " + list);

输出

getList6: [1, 2, 3]

7、Java8 Stream

List<String> list = Stream.of("1", "2", "3").collect(Collectors.toList());
System.out.println("getList7: " + list);

输出

getList7: [1, 2, 3]

8、Java9 List.of

List<String> list = List.of{"1", "2", "3"};
System.out.println("getList8: " + list);

输出

getList8: [1, 2, 3]