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  • PAT甲级——A1051 Pop Sequence

    Given a stack which can keep M numbers at most. Push N numbers in the order of 1, 2, 3, ..., N and pop randomly. You are supposed to tell if a given sequence of numbers is a possible pop sequence of the stack. For example, if M is 5 and N is 7, we can obtain 1, 2, 3, 4, 5, 6, 7 from the stack, but not 3, 2, 1, 7, 5, 6, 4.

    Input Specification:

    Each input file contains one test case. For each case, the first line contains 3 numbers (all no more than 1000): M (the maximum capacity of the stack), N (the length of push sequence), and K (the number of pop sequences to be checked). Then K lines follow, each contains a pop sequence of N numbers. All the numbers in a line are separated by a space.

    Output Specification:

    For each pop sequence, print in one line "YES" if it is indeed a possible pop sequence of the stack, or "NO" if not.

    Sample Input:

    5 7 5
    1 2 3 4 5 6 7
    3 2 1 7 5 6 4
    7 6 5 4 3 2 1
    5 6 4 3 7 2 1
    1 7 6 5 4 3 2
    

    Sample Output:

    YES
    NO
    NO
    YES
    NO


     1 #include <iostream>
     2 #include <stack>
     3 using namespace std;
     4 int M, N, K;
     5 int main()
     6 {
     7     cin >> M >> N >> K;    
     8     for (int i = 0; i < K; ++i)
     9     {
    10         stack<int>s;
    11         int a, b = 1, flag = 1;
    12         for (int j = 0; j < N; ++j)
    13         {
    14             cin >> a;
    15             while (s.size() < M && (s.empty() || s.top() != a))
    16                 s.push(b++);
    17             if (s.top() == a)
    18                 s.pop();
    19             else
    20                 flag = 0;
    21         }
    22         if (flag == 1)
    23             cout << "Yes" << endl;
    24         else
    25             cout << "No" << endl;
    26     }
    27     return 0;
    28 }
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  • 原文地址:https://www.cnblogs.com/zzw1024/p/11280809.html
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