题目链接
题解
比较水。。
常见套路,维护两个堆
Code
#include<bits/stdc++.h>
#define LL long long
#define RG register
using namespace std;
inline int gi() {
int f = 1, s = 0;
char c = getchar();
while (c != '-' && (c < '0' || c > '9')) c = getchar();
if (c == '-') f = -1, c = getchar();
while (c >= '0' && c <= '9') s = s*10+c-'0', c = getchar();
return f == 1 ? s : -s;
}
priority_queue<int> p;
priority_queue<int, vector<int>, greater<int> > q;
const int N = 100010;
int a[N];
char s[10];
int main() {
int n = gi();
for (int i = 1; i <= n; i++) a[i] = gi();
sort(a+1, a+1+n);
int t = gi(), s1 = (n+1)/2, s2 = n-s1;
for (int i = 1; i <= s1; i++)
p.push(a[i]);
for (int i = s1+1; i <= n; i++)
q.push(a[i]);
while (t--) {
cin >> s;
if (s[0] == 'a') {
q.push(gi());
s2++;
if (q.top() < p.top()) {
int tmp = q.top(); q.pop();
q.push(p.top()); p.pop();
p.push(tmp);
}
if (s1 < s2) {
s2--;
s1++;
p.push(q.top());
q.pop();
}
}
else printf("%d
", p.top());
}
return 0;
}