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  • DP单调队列--斜率优化P3195

    题意:https://www.luogu.com.cn/problem/P3195

    思路:https://www.luogu.com.cn/problemnew/solution/P3195

      1 #define IOS ios_base::sync_with_stdio(0); cin.tie(0);
      2 #include <cstdio>//sprintf islower isupper
      3 #include <cstdlib>//malloc  exit strcat itoa system("cls")
      4 #include <iostream>//pair
      5 #include <fstream>//freopen("C:\Users\13606\Desktop\Input.txt","r",stdin);
      6 #include <bitset>
      7 //#include <map>
      8 //#include<unordered_map>
      9 #include <vector>
     10 #include <stack>
     11 #include <set>
     12 #include <string.h>//strstr substr strcat
     13 #include <string>
     14 #include <time.h>// srand(((unsigned)time(NULL))); Seed n=rand()%10 - 0~9;
     15 #include <cmath>
     16 #include <deque>
     17 #include <queue>//priority_queue<int, vector<int>, greater<int> > q;//less
     18 #include <vector>//emplace_back
     19 //#include <math.h>
     20 #include <cassert>
     21 #include <iomanip>
     22 //#include <windows.h>//reverse(a,a+len);// ~ ! ~ ! floor
     23 #include <algorithm>//sort + unique : sz=unique(b+1,b+n+1)-(b+1);+nth_element(first, nth, last, compare)
     24 using namespace std;//next_permutation(a+1,a+1+n);//prev_permutation
     25 //******************
     26 clock_t __START,__END;
     27 double __TOTALTIME;
     28 void _MS(){__START=clock();}
     29 void _ME(){__END=clock();__TOTALTIME=(double)(__END-__START)/CLOCKS_PER_SEC;cout<<"Time: "<<__TOTALTIME<<" s"<<endl;}
     30 //***********************
     31 #define rint register int
     32 #define fo(a,b,c) for(rint a=b;a<=c;++a)
     33 #define fr(a,b,c) for(rint a=b;a>=c;--a)
     34 #define mem(a,b) memset(a,b,sizeof(a))
     35 #define pr printf
     36 #define sc scanf
     37 #define ls rt<<1
     38 #define rs rt<<1|1
     39 typedef pair<int,int> PII;
     40 typedef vector<int> VI;
     41 typedef unsigned long long ull;
     42 typedef long long ll;
     43 typedef double db;
     44 const double E=2.718281828;
     45 const double PI=acos(-1.0);
     46 const ll INF=(1LL<<60);
     47 const int inf=(1<<30);
     48 const double ESP=1e-9;
     49 const int mod=(int)1e9+7;
     50 const int N=(int)1e6+10;
     51 
     52 int n,L;
     53 int a[N];
     54 db dp[N],sum[N];
     55 db A(int x)
     56 {
     57     return sum[x]+x;
     58 }
     59 db B(int x)
     60 {
     61     return sum[x]+x+L+1;
     62 }
     63 db X(int x)
     64 {
     65     return B(x);
     66 }
     67 db Y(int x)
     68 {
     69     return dp[x]+B(x)*B(x);
     70 }
     71 double slope(int a,int b)
     72 {
     73     return 1.0*(Y(a)-Y(b))/(1.0*(X(a)-X(b)));
     74 }
     75 
     76 class mydeque{
     77 public:
     78     int len=1000000;
     79     int p[N];
     80     int l,r,tot;
     81     void init()
     82     {
     83         l=1;r=1;
     84         tot=1;
     85     }
     86     int size()
     87     {
     88         return tot;
     89     }
     90     int pos(int x)
     91     {
     92         return (x+len)%len;
     93     }
     94     int f()
     95     {
     96         return p[l];
     97     }
     98     int b()
     99     {
    100         return p[r];
    101     }
    102     void pf(int x)
    103     {
    104         tot++;
    105         l=pos(l-1);
    106         p[l]=x;
    107     }
    108     void pb(int x)
    109     {
    110         tot++;
    111         r=pos(r+1);
    112         p[r]=x;
    113     }
    114     void popf()
    115     {
    116         p[l]=0;
    117         l=pos(l+1);
    118         tot--;
    119     }
    120     void popb()
    121     {
    122         p[r]=0;
    123         r=pos(r-1);
    124         tot--;
    125     }
    126 }q;
    127 
    128 int main()
    129 {
    130     q.init();//初始化有dp[0](l=r=1而不是l=1,r=0,tot=0),因为要用到
    131     sc("%d%d",&n,&L);
    132     for(int i=1;i<=n;++i)sc("%d",&a[i]),sum[i]=a[i]+sum[i-1];
    133     for(int i=1;i<=n;++i)
    134     {
    135         while(q.l<q.r&&slope(q.f(),q.p[q.pos(q.l+1)])<2.0*A(i))q.popf();
    136         dp[i]=dp[q.f()]+(A(i)-B(q.f()))*(A(i)-B(q.f()));
    137         while(q.l<q.r&&slope(q.p[q.pos(q.r-1)],q.b())>slope(q.p[q.pos(q.r-1)],i))q.popb();
    138         q.pb(i);
    139     }
    140     pr("%lld
    ",(ll)dp[n]);
    141     return 0;
    142 }
    143 
    144 /**************************************************************************************/
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  • 原文地址:https://www.cnblogs.com/--HPY-7m/p/12005024.html
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