zoukankan      html  css  js  c++  java
  • Making Huge Palindromes (KMP处理回文串)

    1258 - Making Huge Palindromes
    PDF (English) Statistics Forum
    Time Limit: 1 second(s) Memory Limit: 32 MB
    A string is said to be a palindrome if it remains same when read backwards. So, 'abba', 'madam' both are palindromes, but 'adam' is not.

    Now you are given a non-empty string S, containing only lowercase English letters. The given string may or may not be palindrome. Your task is to make it a palindrome. But you are only allowed to add characters at the right side of the string. And of course you can add any character you want, but the resulting string has to be a palindrome, and the length of the palindrome should be as small as possible.

    For example, the string is 'bababa'. You can make many palindromes including

    bababababab

    babababab

    bababab

    Since we want a palindrome with minimum length, the solution is 'bababab' cause its length is minimum.

    Input
    Input starts with an integer T (≤ 10), denoting the number of test cases.

    Each case starts with a line containing a string S. You can assume that 1 ≤ length(S) ≤ 106.

    Output
    For each case, print the case number and the length of the shortest palindrome you can make with S.

    Sample Input
    Output for Sample Input
    4

    bababababa

    pqrs

    madamimadam

    anncbaaababaaa

    Case 1: 11

    Case 2: 7

    Case 3: 11

    Case 4: 19

    给出一个字符串,求得要在最后加几个字符能组成最短的回文字符串,输出这个回文字符串的长度

    把字符翻转过来,当成模板串,然后再和原串进行匹配,到最后的时候,求出匹配的长度,这个长度也就是在原串中已经构成回文的那部分的最大长度j,然后len-j 是不能匹配的长度,加上len 得到处理后的最短的回文字符串的长度了

    例如:

    12122   

    想把它转化为回文的,那么先求出翻转后的字符串

    22121

    然后就是找原串的后缀和翻转串的前缀的最多匹配的个数了,kmp跑完之后,j就是匹配的个数,本例即为 22 

    那就把翻转串的剩下的字符串(长度为len-j)连接在原串上,就得到了最后的回文串结果,长度为len-j+len,也就是2*len-j

    证明完毕!

     1 #include <stdio.h>
     2 #include <algorithm>
     3 #include <iostream>
     4 #include <stdbool.h>
     5 #include <stdlib.h>
     6 #include <string>
     7 #include <string.h>
     8 #include <math.h>
     9 #include <vector>
    10 #include <queue>
    11 #include <stack>
    12 #include <set>
    13 #include <map>
    14 
    15 #define INF 0x3f3f3f3f
    16 #define LL long long
    17 #define MAXN 1000005
    18 #define mod 1000000007
    19 using namespace std;
    20 
    21 char S[MAXN],T[MAXN];
    22 int nexts[MAXN];
    23 
    24 
    25 
    26 void GetNext(char *str)
    27 {
    28     int i=0,j=-1;
    29     nexts[0] = -1;
    30     int len = strlen(str);
    31     while (i<len)
    32     {
    33         if (j == -1 || str[i]==str[j])
    34         {
    35             i++;
    36             j++;
    37             nexts[i] = j;
    38         } else
    39             j = nexts[j];
    40     }
    41 }
    42 
    43 int KMP(char *S,char *T)
    44 {
    45     GetNext(T);
    46     int j = 0;
    47     int i = 0;
    48     int len_s = strlen(S);
    49     int len_t = strlen(T);
    50     int cnt = 0;
    51     while (i<len_s)
    52     {
    53         if (j==-1 || S[i]==T[j])
    54         {
    55             i++;
    56             j++;
    57         }
    58         else
    59             j = nexts[j];
    60     }
    61     return 2*i-j;
    62 }
    63 
    64 int main()
    65 {
    66     int t;
    67     scanf("%d",&t);
    68     int k=1;
    69     while (t--)
    70     {
    71         scanf("%s",S);
    72         getchar();
    73         int len = strlen(S);
    74         for (int i=0;i<len;i++)
    75             T[i] = S[len-i-1];
    76         printf("Case %d: %d
    ",k++,KMP(S,T));
    77     }
    78     return 0;
    79 }



  • 相关阅读:
    bootstrap添加模态窗后,再弹出消息提示框后,原先的滚动条消失
    改变input[type=file]的默认样式
    javascript判断访问终端,手机端自动跳转
    sublime安装插件autoprefixer
    android 自动化压力测试-monkey 1 实践
    python 网络编程-TCP/UDP
    python 正则表达式
    Python 读写excel数据
    Python 删除列表中的重复数据
    Python python 基本语法
  • 原文地址:https://www.cnblogs.com/-Ackerman/p/11294908.html
Copyright © 2011-2022 走看看