Description
Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a straight line at positions x1,...,xN (0 <= xi <= 1,000,000,000).
His C (2 <= C <= N) cows don't like this barn layout and become aggressive towards each other once put into a stall. To prevent the cows from hurting each other, FJ want to assign the cows to the stalls, such that the minimum distance between any two of them is as large as possible. What is the largest minimum distance?
His C (2 <= C <= N) cows don't like this barn layout and become aggressive towards each other once put into a stall. To prevent the cows from hurting each other, FJ want to assign the cows to the stalls, such that the minimum distance between any two of them is as large as possible. What is the largest minimum distance?
Input
* Line 1: Two space-separated integers: N and C
* Lines 2..N+1: Line i+1 contains an integer stall location, xi
* Lines 2..N+1: Line i+1 contains an integer stall location, xi
Output
* Line 1: One integer: the largest minimum distance
Sample Input
5 3 1 2 8 4 9
Sample Output
3
代码;
#include<cstdio> #include<iostream> #include<cmath> #include<algorithm> #include<cstring> using namespace std ; #define MAXN 1000010 int a[MAXN] ; bool find( int x , int n , int c ) { int i ,mun = 1 , p = a[1]; for( i = 2 ; i <= n ;i++) { if( a[i] - p >= x ) { mun++ ; p = a[i]; } } if( mun >= c ) return 1 ;// 如果超过c 则说明mid小了 else return 0 ; } int main() { int mid , low , high ; int i , n , m , c ; while( cin >> n >> c ) { for( i = 1 ; i <= n ;i++) scanf( "%d" , &a[i] ) ; // 因为输入不是有序的 sort( a + 1 , a + 1 + n ) ; low = 0 ; high = ( a[1] + a[n] ) / ( c - 1 ) ; while( low <= high ) { mid = ( low + high ) / 2 ; if( find(mid , n , c )) low = mid + 1 ; else high = mid - 1 ; } cout << low - 1 << endl ; } }