What Are You Talking About

What Are You Talking About

Time Limit : 10000/5000ms (Java/Other)   Memory Limit : 102400/204800K (Java/Other)

Total Submission(s) : 20   Accepted Submission(s) : 6

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Problem Description

Ignatius is so lucky that he met a Martian yesterday. But he didn't know the language the Martians use. The Martian gives him a history book of Mars and a dictionary when it leaves. Now Ignatius want to translate the history book into English. Can you help him?

Input

The problem has only one test case, the test case consists of two parts, the dictionary part and the book part. The dictionary part starts with a single line contains a string "START", this string should be ignored, then some lines follow, each line contains two strings, the first one is a word in English, the second one is the corresponding word in Martian's language. A line with a single string "END" indicates the end of the directory part, and this string should be ignored. The book part starts with a single line contains a string "START", this string should be ignored, then an article written in Martian's language. You should translate the article into English with the dictionary. If you find the word in the dictionary you should translate it and write the new word into your translation, if you can't find the word in the dictionary you do not have to translate it, and just copy the old word to your translation. Space(' '), tab(' '), enter(' ') and all the punctuation should not be translated. A line with a single string "END" indicates the end of the book part, and that's also the end of the input. All the words are in the lowercase, and each word will contain at most 10 characters, and each line will contain at most 3000 characters.

Output

In this problem, you have to output the translation of the history book.

Sample Input

START
from fiwo
hello difh
mars riwosf
earth fnnvk
like fiiwj
END
START
difh, i'm fiwo riwosf.
i fiiwj fnnvk!
END

Sample Output

hello, i'm from mars.
i like earth!

Hint

Huge input, scanf is recommended.

Author

Ignatius.L

题意：开始时START

创建一本单词本

END结束；

START:

翻译开始：

END翻译结束；

这题容易联想到STL 里的 map

#include<map>

 

map<类型,类型> ma；

map<类型,类型>::iterator it; 定义一个迭代器

it=ma.find(对象)

因为 find() 返回迭代器；

it->second 就返回 值

map(key,value)

it->second 返回value;

#include<iostream>
#include<string>
#include <algorithm>
#include<map>
using namespace std;
int main()
{
    
    //a.insert(pair<string,string>("aaaa","bbb"));


    string x,y;
    while(cin>>x)
    {
        map<string,string> mapp;    
         map<string,string>::iterator it;
        if(x=="START")
        {
            while(cin>>x)
            {
                if(x=="END")
                {
                    break;
                }
                cin>>y;
            
             mapp.insert(pair<string,string>(y,x));
            }//构建地图；//地图完成
            cin>>x;
            if(x=="START")//翻译开始+++++
            {
                char word[3005];
                getchar();
                while(gets(word))
                {
                    if(word[0]=='E'&&word[1]=='N'&&word[2]=='D')
                        break;//翻译结束


                    //翻译开始
                    int num;//
                    int numm=strlen(word); 
                    for(num=0;num<numm;)
                    {
                        
                        if((word[num]>='a'&&word[num]<='z')||(word[num]>='A'&&word[num]<='Z'))//找出单词并输出
                        {
                            string words;
                            string linshi;
                            while((word[num]>='a'&&word[num]<='z')||(word[num]>='A'&&word[num]<='Z'))
                            {
                                linshi=word[num++];
                                words.insert(words.length(),linshi);
                            }//得到单词；
                            it=mapp.find(words);
                            if(it!=mapp.end())
                            {
                                
                                cout<<it->second;
                            
                            }
                            else
                            {
                                cout<<words;
                            
                            }
                        
                        }
                        else 
                        {
                            printf("%c",word[num++]);//词典没有就原样输出

                        }
                    
                    
                    }
                    printf("
");
                
                }
            }


        }
        else
        {break;}

    }

    return 0;
}