1002. A+B for Polynomials (25)
时间限制
400 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue
This time, you are supposed to find A+B where A and B are two polynomials.
Input
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10,0 <= NK < ... < N2 < N1 <=1000.
Output
For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.
Sample Input2 1 2.4 0 3.2 2 2 1.5 1 0.5Sample Output
3 2 1.5 1 2.9 0 3.2
题意给一个n 项多项式。在给第几项的 n次,和系数。
相加
#include <iostream> #include<string.h> #include<stdio.h> #include<iomanip> using namespace std; double a[1000]; int main() { int n, m; int max=0; memset(a,0,sizeof a); cin>>n; int c; double d; for(int i=0;i<n;i++) { cin>>c>>d; a[c]=a[c]+d; if(c>max) max=c; } cin>>m; for(int i=0;i<m;i++) { cin>>c>>d; a[c]=a[c]+d; if(c>max) max=c; } int num=0; for(int i=0;i<=max;i++) { if(a[i]!=0) num++; } cout<<num; for(int i=max;i>=0;i--) { if(a[i]!=0) { cout<<" "<<i<<" "; cout<<fixed<<setprecision(1)<<a[i]; } } cout<<endl; return 0; }
注意结果保存1位