zoukankan      html  css  js  c++  java
  • 牛客第二场A-run

    链接:https://www.nowcoder.com/acm/contest/140/A
    来源:牛客网
    
    White Cloud is exercising in the playground.
    White Cloud can walk 1 meters or run k meters per second.
    Since White Cloud is tired,it can't run for two or more continuous seconds.
    White Cloud will move L to R meters. It wants to know how many different ways there are to achieve its goal.
    Two ways are different if and only if they move different meters or spend different seconds or in one second, one of them walks and the other runs.
    
    输入描述:
    The first line of input contains 2 integers Q and k.Q is the number of queries.(Q<=100000,2<=k<=100000)
    For the next Q lines,each line contains two integers L and R.(1<=L<=R<=100000)
    输出描述:
    For each query,print a line which contains an integer,denoting the answer of the query modulo 1000000007.
    示例1
    输入
    复制
    3 3
    3 3
    1 4
    1 5
    输出
    复制
    2
    7
    11

    dp。dp[i][j]表示到i这一步是跑的(1)还是走的(0)。

    #include<iostream>
    #include<stdio.h>
    #include<string.h>
    using namespace std;
    long long dp[100005][2];
    long long sum[100005];
    int main()
    {
        long long   n,m;
          scanf("%lld%lld",&n,&m);
         memset(dp,0,sizeof dp);
            dp[0][0]=1;
            for(int i=1;i<=100000;i++)
            {
                dp[i][0]=(dp[i-1][0]+dp[i-1][1])%1000000007;
                if(i>=m)
                dp[i][1]=dp[i-m][0]%1000000007;
            }
            sum[0]=1;
            for(int i=1;i<=100000;i++)
            {
                sum[i]=sum[i-1]+dp[i][0]+dp[i][1];
                sum[i]=sum[i]%1000000007;
            }
        for(int i=0;i<n;i++)
        {
            long long q,w;
            scanf("%lld%lld",&q,&w);
          cout<<(sum[w]+1000000007-sum[q-1])%1000000007<<endl;
        }
        return 0;
    }
  • 相关阅读:
    jsp Servlet 3.0文件上传
    Android 模拟多线程下载
    Android之Handler用法总结
    Android 手机模拟器安卓软件
    Json笔记
    java.lang.ClassNotFoundException: com.google.gson.Gson”
    关于MD5加密
    Android 抽屉布局
    Android ListView 适配器
    如何在安裝SELinux的环境执行Quartus II
  • 原文地址:https://www.cnblogs.com/2014slx/p/9364637.html
Copyright © 2011-2022 走看看