A
#include <bits/stdc++.h>
using namespace std;
int n, a, b, c;
int main()
{
scanf("%d", &n);
for (int i = 1; i <= n; ++i)
{
scanf("%d%d%d", &a, &b, &c);
int cnt = 0;
if (a >= 10) ++cnt;
if (b >= 10) ++cnt;
if (c >= 10) ++cnt;
if (i != 1) puts("");
printf("%d %d %d
", a, b, c);
if (cnt == 0) puts("zilch");
else if (cnt == 1) puts("double");
else if (cnt == 2) puts("double-double");
else puts("triple-double");
}
return 0;
}
B
#include <bits/stdc++.h>
using namespace std;
int t, n;
int f[26];
char a[3], b[3], s[55];
int find(int x)
{
if (x == f[x]) return x;
return f[x] = find(f[x]);
}
bool same(int x, int y)
{
x = find(x), y = find(y);
return x == y;
}
void unit(int x, int y)
{
x = find(x), y = find(y);
f[y] = x;
}
int main()
{
scanf("%d", &t);
for (int cas = 1; cas <= t; ++cas)
{
if (cas != 1) puts("");
printf("Test case #%d:
", cas);
for (int i = 0; i < 26; ++i) f[i] = i;
scanf("%d", &n);
for (int i = 1; i <= n; ++i)
{
scanf("%s%s", a + 1, b + 1);
unit(a[1] - 'a', b[1] - 'a');
}
scanf("%d", &n);
for (int i = 1; i <= n; ++i)
{
scanf("%s", s + 1);
printf("%s ", s + 1);
int len = strlen(s + 1), flag = 1;
for (int i = 1, j = len; i < j; ++i, --j)
if (!same(s[i] - 'a', s[j] - 'a')) { flag = 0; break; }
if (flag) puts("YES");
else puts("NO");
}
}
return 0;
}
C
#include <bits/stdc++.h>
using namespace std;
int h[55], l[55], t, n, k;
int main()
{
scanf("%d", &t);
for (int cas = 1; cas <= t; ++cas)
{
if (cas != 1) puts("");
int ans = 0;
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; ++i) h[i] = l[i] = 0;
for (int i = 1; i <= k; ++i)
{
int a, b;
scanf("%d%d", &a, &b);
if (h[a] && l[b]) ++ans;
h[a] = l[b] = 1;
}
printf("Strategy #%d: %d
", cas, ans);
}
return 0;
}
D
#include <bits/stdc++.h>
#define ll long long
using namespace std;
int t, n, m, k, g;
ll sum[25];
int main()
{
scanf("%d", &t);
for (int cas = 1; cas <= t; ++cas)
{
if (cas != 1) puts("");
printf("CD #%d:
", cas);
scanf("%d%d", &n, &k);
for (int i = 1; i <= n; ++i) scanf("%d", &m), sum[i] = sum[i - 1] + m;
scanf("%d", &m);
for (int i = 1; i <= m; ++i)
{
scanf("%d", &g); ll ans = 0;
for (int j = 1, c; j <= g; ++j)
{
int a; scanf("%d", &a);
if (j & 1) ans += a, c = sum[k] - sum[k - 1] - a % (sum[k] - sum[k - 1]);
else
{
if (c == sum[k] - sum[k - 1]) c = 0;
if (a <= c) {ans += a; continue;}
a -= c, ans += c;
ans += a / sum[n] * (sum[k] - sum[k - 1]);
a = a % sum[n] - (sum[n] - sum[k] + sum[k - 1]);
if (a > 0) ans += a;
}
}
printf("%lld
", ans);
}
}
return 0;
}
E
#include <bits/stdc++.h>
#define P pair<int, int>
using namespace std;
int n, m, cnt, tot, k, t;
int mp[25][25], d[4][2] = { {0,1}, {0,-1}, {1,0}, {-1, 0} };
char s[105], ans[5] = "RLDU";
bool work(int de, P p)
{
for (int i = 2; s[i]; ++i)
{
p.first += d[de][0], p.second += d[de][1];
if (p.first < 1) p.first = n;
else if (p.first > n) p.first = 1;
if (p.second < 1) p.second = m;
else if (p.second > m) p.second = 1;
if (mp[p.first][p.second] != s[i] - 'A') return false;
}
return true;
}
int main()
{
scanf("%d", &t);
for (int cas = 1; cas <= t; ++cas)
{
vector<P> ve[26];
if (cas != 1) puts("");
printf("Word search puzzle #%d:
", cas);
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; ++i)
for (int j = 1; j <= m; ++j)
{
char c = getchar();
while (c > 'Z' || c < 'A') c = getchar();
mp[i][j] = c - 'A';
ve[c - 'A'].push_back({ i, j });
}
scanf("%d", &k);
for (int i = 1; i <= k; ++i)
{
scanf("%s", s + 1);
int ch = s[1] - 'A', flag = 1;
for (P p : ve[ch])
{
for (int de = 0; de < 4; ++de)
if (work(de, p))
{
printf("%c %d %d %s
", ans[de], p.first, p.second, s + 1);
flag = 0;
break;
}
if (!flag) break;
}
}
}
return 0;
}
F(eps用多了误差就大了)
#include <bits/stdc++.h>
#define P pair<double, double>
#define eps 1e-6
using namespace std;
int n, t;
P p[55];
double dis(P a, P b)
{
return (a.first - b.first) * (a.first - b.first) +
(a.second - b.second) * (a.second - b.second);
}
bool same(double a, double b)
{
return abs(a - b) <= eps;
}
bool same(P a, P b)
{
return (same(a.first, b.first) && same(a.second, b.second));
}
bool is(P a, P b, P c)
{
return same(dis(a, c), dis(a, b) + dis(b, c));
}
int main()
{
scanf("%d", &t);
for (int cas = 1; cas <= t; ++cas)
{
scanf("%d", &n);
for (int i = 1; i <= n; ++i) scanf("%lf%lf", &p[i].first, &p[i].second);
int ans = 0;
for (int i = 1; i <= n; ++i)
for (int j = i + 1; j <= n; ++j)
for (int k = 1; k <= n; ++k)
if (k != i && k != j)
{
P mid = { (p[i].first + p[j].first) / 2,
(p[i].second + p[j].second) / 2 };
if (!same(mid, p[k])) continue;
for (int x = 1; x <= n; ++x)
if (x != i && x != j && x != k)
{
if (same(dis(p[x], p[k]), dis(p[i], p[j])) &&
is(p[i], p[k], p[x])) ++ans;
}
}
if (cas != 1) puts("");
printf("Set #%d: %d
", cas, ans);
}
return 0;
}
G
(在A,B都能防御的时候,要分情况要么A防御,要么B,所以分两组(A,B)和(B、A),当一情况(二者都能防御且漏刀数小于等于另一种情况)则把另一种情况直接转换到当前情景(两者都能防御)然后继续分两组)
#include <bits/stdc++.h>
using namespace std;
int n, t, a[1005], m, b[3];
int main()
{
scanf("%d", &t);
for (int cas = 1; cas <= t; ++cas)
{
scanf("%d", &n);
int ans = 0, lans = 0;
for (int i = 1; i <= n; ++i) scanf("%d", a + i);
sort(a + 1, a + 1 + n);
scanf("%d", &m);
int x = 0, y = 0, lx = 0, ly = 0;
for (int i = 1; i <= m; ++i) scanf("%d", &b[i]);
if (m == 1)
for (int i = 1; i <= n; ++i)
if (x <= a[i]) x = a[i] + b[1];
else ++ans;
else
for (int i = 1; i <= n; ++i)
{
if (lx <= a[i] && ly <= a[i] && lans <= ans)
ans = lans, x = lx, y = ly;
if (x <= a[i] && y <= a[i] && ans <= lans)
lans = ans, lx = x, ly = y;
if (x <= a[i]) x = a[i] + b[1];
else if (y <= a[i]) y = a[i] + b[2];
else ++ans;
if (ly <= a[i]) ly = a[i] + b[2];
else if (lx <= a[i]) lx = a[i] + b[1];
else ++lans;
}
if (cas != 1) puts("");
if (m != 1) printf("Mission #%d: %d
", cas, min(ans, lans));
else printf("Mission #%d: %d
", cas, ans);
}
return 0;
}
H
#include <bits/stdc++.h>
#define ll long long
using namespace std;
const int maxn = 1e7 + 5;
int n, t, a[maxn], x;
int main()
{
scanf("%d", &t);
for(int cas = 1; cas <= t; ++cas)
{
ll ans=0; int mx = 0;
scanf("%d",&n);
memset(a,0,sizeof(a));
for(int i = 1; i <= n; ++i) scanf("%d", &x), ++a[x], mx = max(mx, x);
ans += (ll)a[0] * (n - a[0]) + (ll)a[1] * (n - a[0] - a[1]);
for(int i = 2; i <= mx; ++i)
if(a[i])
for(int j = 2; j <= mx / i; ++j) ans += (ll)a[i] * a[j * i];
printf("Test case #%d: %lld
", cas, ans);
}
return 0;
}
I
#include <bits/stdc++.h>
#define ll long long
#define P pair<int, int>
using namespace std;
int n, m, k, t, tot;
int mod = 1000000007;
int cnt[20];
P p[20];
ll dfs(int k, int tota)
{
if (tota == n) { return 1; }
ll ans = 0;
for (int i = 1; i <= tot; ++i)
if (cnt[i] && (p[i].first == k || p[i].second == k))
{
ll res = 0;
--cnt[i];
res = dfs(p[i].first == k ? p[i].second : p[i].first, tota + 1);
++cnt[i];
ans += res * cnt[i];
}
return ans;
}
int main()
{
scanf("%d", &t);
for (int cas = 1; cas <= t; ++cas)
{
scanf("%d", &n);
tot = 0;
for (int i = 1; i <= n; ++i)
{
scanf("%d%d", &p[i].first, &p[i].second);
if (p[i].first > p[i].second) swap(p[i].first, p[i].second);
cnt[i] = 0;
}
sort(p + 1, p + 1 + n);
for (int i = 1; i <= n; ++i)
{
int j = i;
while (i + 1 <= n && p[i] == p[i + 1]) ++i;
p[++tot] = p[i], cnt[tot] = i - j + 1;
}
ll ans = 0;
for (int i = 1; i <= tot; ++i)
{
--cnt[i];
ll res = dfs(p[i].first, 1);
if (p[i].first != p[i].second) res += dfs(p[i].second, 1);
++cnt[i];
ans += res * cnt[i];
}
int flag = (tot == 1 && p[1].first != p[1].second);
printf("%lld", (ans >> flag) % mod);
if (cas < t) puts("");
}
return 0;
}
J
#include <bits/stdc++.h>
#define P pair<int, int>
#define PP pair<int, P>
using namespace std;
int t, n, m;
int mp[505][505], vis[505][505];
int d[4][2] = { {1, 0}, {-1, 0}, {0, 1} , {0, -1} };
bool check(int mid)
{
for (int i = 1; i <= n; ++i)
for (int j = 1; j <= m; ++j) vis[i][j] = 0;
vis[1][1] = 1;
queue<PP> q; q.push({ 1, {1, 1} });
while (!q.empty())
{
int dis = q.front().first;
P p = q.front().second; q.pop();
for (int i = 0; i < 4; ++i)
{
int x = p.first + d[i][0], y = p.second + d[i][1];
if (x < 1 || x > n || y < 1 || y > m) continue;
if (mp[x][y] - dis < mid || vis[x][y]) continue;
if (x == n && y == m) return true;
vis[x][y] = 1;
q.push({ dis + 1, {x, y} });
}
}
return false;
}
int main()
{
scanf("%d", &t);
while (t--)
{
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; ++i)
for (int j = 1; j <= m; ++j) scanf("%d", &mp[i][j]);
if (!mp[1][1]) { puts("impossible"); continue; }
if (m + n == 2) {printf("%d
", mp[1][1]); continue; }
int r = mp[1][1], l = 0;
while (l < r)
{
int mid = (l + r + 1) >> 1;
if (check(mid)) l = mid;
else r = mid - 1;
}
if (!l) puts("impossible");
else printf("%d
", l);
}
return 0;
}
K
(太菜了,花里胡哨的想,拆了绝对值,就是搜索)
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 5e5 + 5;
int dist[N], t[N], h[N], k, n;
int main()
{
scanf("%d", &k);
for (int cas = 1; cas <= k; ++cas)
{
scanf("%d", &n);
map<int, vector<int> > g1, g2;
map<int, bool> st1, st2;
for(int i=1;i<=n;i++) scanf("%d", t + i);
for(int i=1;i<=n;i++) scanf("%d", h + i);
for(int i=1;i<=n;i++)
{
g1[t[i] + h[i]].push_back(i);
g2[t[i] - h[i]].push_back(i);
}
memset(dist, -1, sizeof dist);
dist[1] = 0;
queue<int> que;
que.push(1);
while (que.size())
{
int node = que.front(); que.pop();
if(!st1[t[node] + h[node]])
{
st1[t[node] + h[node]] = 1;
for(auto &new_node : g1[t[node] + h[node]])
if(dist[new_node] == -1)
dist[new_node] = dist[node] + 1, que.push(new_node);
}
if(!st2[t[node] - h[node]])
{
st2[t[node] - h[node]] = 1;
for(auto &new_node : g2[t[node] - h[node]])
if(dist[new_node] == -1)
dist[new_node] = dist[node] + 1, que.push(new_node);
}
}
printf("Field #%d: %d
", cas, dist[n]);
}
return 0;
}