ICPC Asia Taipei-Hsinchu Regional 2019

A(题解看注释)

#include <bits/stdc++.h>
#define P pair<int, int>
using namespace std;

struct mp
{
    int p[7][7];
    bool friend operator <(const mp &a, const mp &b)
    {
        for (int i =1 ; i <= 6; ++i)
            for (int j = 1; j <= 6; ++j)
                if (a.p[i][j] != b.p[i][j]) return a.p[i][j] < b.p[i][j];
        return false;
    }
};

struct node
{
    P a[11], b[11]; // a【i】表示第i辆车的车头坐标，b【i】车尾
    int cnt;
    mp p;
}c;

int n, ans = -1;
int d[4][2] = {{0, 1}, {0, -1}, {1, 0}, {-1, 0}}; // 方向
set<mp> st; //剪枝
queue<node> q;
               
bool move(node &res, int id, int de)
{
    P &a = res.a[id], &b = res.b[id]; mp &p = res.p;
    if (a.first == b.first && de > 1) return false; //移动不合法
    if (a.second == b.second && de < 2) return false;
    a.first += d[de][0], a.second += d[de][1];
    if (a.first < 1 || a.first > 6 || a.second < 1|| a.second > 6) return false;
    if (p.p[a.first][a.second] != id && p.p[a.first][a.second] != 0) return false;
    b.first += d[de][0], b.second += d[de][1];
    if (b.first < 1 || b.first > 6 || b.second < 1|| b.second > 6) return false;
    if (p.p[b.first][b.second] != id && p.p[b.first][b.second] != 0) return false;
    if (de == 0 || de == 2) 
        p.p[a.first - d[de][0]][a.second - d[de][1]] = 0, p.p[b.first][b.second] = id;
    else if (de == 1 || de == 3) 
        p.p[b.first - d[de][0]][b.second - d[de][1]] = 0, p.p[a.first][a.second] = id;
    return true;
}

int main()
{
    for (int i = 1; i <= 6; ++i)
        for (int j = 1; j <= 6; ++j)
        {
            int m; cin >> m; //以后尽量用cin
            if (!m) continue;
            if (c.a[m].first == 0) c.a[m] = {i, j};
            else c.b[m] = {i, j};
            n = max(n, m); // 有几辆车
            c.p.p[i][j] = m;
        }
    st.insert(c.p), q.push(c);
    while (!q.empty())
    {
        c = q.front(); q.pop();
        if (c.a[1] == make_pair(3, 5) && c.b[1] == make_pair(3, 6)) 
        { ans = c.cnt + 2; break;}
        if (c.cnt >= 8) continue; //剪枝
        for (int i = 1; i <= n; ++i)
            for (int j = 0; j < 4; ++j) //方向
            {
                node res = c; ++res.cnt;
                if (move(res, i, j))
                    if (st.count(res.p)) continue;
                    else st.insert(res.p), q.push(res);
            }
    }
    printf("%d", ans);
    return 0;
}

　　

C

#include <bits/stdc++.h>
using namespace std;

int n, a[55], flag;

int main()
{
    cin >> n;
    for (int i = 1; i <= n; ++i) cin >> a[i];
    for (int i = 1; i <= n; ++i)
       for (int j = 1; j <= n; ++j)
           if (i != j)
                for (int k = j + 1; k <= n; ++k)
                    if (i != k)
                        if ((a[k] - a[j]) % a[i]) flag = 1;
    if (flag) puts("no");
    else puts("yes");
    return 0;
}

　　

D

#include <bits/stdc++.h>
using namespace std;

char a[10] = "bubble", b[10] = "tapioka", s[10000000];

int main()
{
    int flag = 1;
    while (cin >> s)
        if (strcmp(a, s) && strcmp(b, s)) cout << s << ' ', flag = 0;
    if (flag) cout << "nothing";
    return 0;
}

　　

E

#include <bits/stdc++.h>
using namespace std;

const int maxn = 1e6;

int t, k, len, n;
int a[2000];

int main()
{
    cin >>t; a[1] = -1;
    while (t--)
    {
        cin >> k >> len; n = 2;
        if (len >= 2000) {puts("-1"); continue;}
        int sum = max((k - 1) / maxn + 3, len);
        k = k + sum;
        for (int &i = n; i <= len || k > 0; ++i)
            if (k >= 1e6) a[i] = 1e6, k -= 1e6;
            else if (k > 0) a[i] = k, k = 0;
            else a[i] = 0;
        cout << n - 1 << '
';
        for (int i = 1; i < n; ++i) cout << a[i] << ' ';
        puts("");
    }
    return 0;
}

　　

H

#include <bits/stdc++.h>
#define ll long long
using namespace std;

int t, n;

int main()
{
    cin >> t;
    while (t--)
    {
        cin >> n;
        cout << ((ll)n * (n + 1) ^ (n + 1)) << '
';
    }
    return 0;
}

　　

J

#include <bits/stdc++.h>
using namespace std;

int s[505], t, n, m, mp[16][505], v[505], ans;
vector<int> ve[505];

bool cmp(int a, int b)
{
    return ve[a].size() < ve[b].size();
}

void dfs(int k, int tot)
{
    while (k <= n && v[s[k]]) ++k;
    if (k > n) { ans = min(ans, tot); return; }
    if (tot + 1 >= ans) return;
    for (int i = 0; i < ve[s[k]].size(); ++i)
    {
        int& id = ve[s[k]][i];
        for (int j = 1; j <= n; ++j) v[j] += mp[id][j];
        dfs(k + 1, tot + 1);
        for (int j = 1; j <= n; ++j) v[j] -= mp[id][j];
    }
}

int main()
{
    scanf("%d", &t);
    while (t--)
    {
        scanf("%d%d", &n, &m); ans = m;
        for (int i = 1; i <= n; ++i)
            vector<int>().swap(ve[i]), v[i] = 0, s[i] = i;
        for (int i = 1; i <= m; ++i)
            for (int j = 1; j <= n; ++j)
            {
                char c = getchar();
                while (c != '0' && c != '1') c = getchar();
                if (c == '1') mp[i][j] = 1, ve[j].emplace_back(i);
                else mp[i][j] = 0;
            }
        sort(s + 1, s + 1 + n, cmp);
        if (ve[s[1]].empty()) { puts("-1"); continue; }
        dfs(1, 0);
        printf("%d
", ans);
    }
    return 0;
}

　　

K

#include <bits/stdc++.h>
using namespace std;

int t, n, a;
priority_queue<int, vector<int>, greater<int> > q;

int main()
{
    cin >> t;
    while (t--)
    {
        cin >> n;
        while (n--) cin >> a, q.push(a);
        int ans = 0;
        while (!q.empty())
        {
            int a = q.top(), b; q.pop();
            if (!q.empty()) b = q.top(), q.pop();
            else break;
            ans += a + b, q.push(a + b);
        }
        cout << ans << '
';
    }
    return 0;
}