题目描述:ZigZag Conversion
The string "PAYPALISHIRING"
is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3)
should return "PAHNAPLSIIGYIR"
.
分析:
对于每一层垂直元素的坐标 ( i, j ) = ( j + 1) ∗ n + i;对于每两层垂直元素之间的插入元素(斜对角元素), ( i, j ) = ( j + 1) ∗ n − i。
代码如下:
class Solution { public: string convert(string s, int nRows) { if(nRows <= 1 || s.size() <= 1) return s; string result; for(int i = 0; i < nRows; i++){ for(int j = 0, index = i; index < s.size(); j++, index = (2 * nRows - 2) * j + i){ result.append(1, s[index]); if(i == 0 || i == nRows - 1) continue; if(index + (nRows - i - 1) * 2 < s.size()) result.append(1, s[index + (nRows - i - 1) * 2]); } } return result; } };