Given two binary trees, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical and the nodes have the same value.
Example 1:
Input: 1 1
/ /
2 3 2 3
[1,2,3], [1,2,3]
Output: true
Example 2:
Input: 1 1
/
2 2
[1,2], [1,null,2]
Output: false
Example 3:
<b>Input:</b> 1 1
/ /
2 1 1 2
[1,2,1], [1,1,2]
<b>Output:</b> false
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isSameTree(TreeNode* p, TreeNode* q) { //树的遍历
if((p==NULL&&q!=NULL)||(p!=NULL&&q==NULL))
return false;
else if(p==NULL&&q==NULL)
return true;
else if(p->val!=q->val)
return false;
//if(p!=NULL&&q!=NULL){
if(!isSameTree(p->left, q->left))
return false;
if(!isSameTree(p->right, q->right))
return false;
// }
return true;
}
};