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  • 【河南省多校脸萌第六场 】密码锁

    【链接】点击打开链接


    【题意】


    在这里写题意

    【题解】


    bfs+map

    【错的次数】


    0

    【反思】


    在这了写反思

    【代码】

    #include <cstdio>
    #include <iostream>
    #include <algorithm>
    #include <cstring>
    #include <vector>
    #include <map>
    #include <queue>
    #include <iomanip>
    #include <set>
    #include <cstdlib>
    #include <cmath>
    #include <bitset>
    using namespace std;
    #define lson l,m,rt<<1
    #define rson m+1,r,rt<<1|1
    #define LL long long
    #define rep1(i,a,b) for (int i = a;i <= b;i++)
    #define rep2(i,a,b) for (int i = a;i >= b;i--)
    #define mp make_pair
    #define pb emplace_back
    #define fi first
    #define se second
    #define ld long double
    #define ms(x,y) memset(x,y,sizeof x)
    #define ri(x) scanf("%d",&x)
    #define rl(x) scanf("%lld",&x)
    #define rs(x) scanf("%s",x)
    #define rf(x) scnaf("%lf",&x)
    #define oi(x) printf("%d",x)
    #define ol(x) printf("%lld",x)
    #define oc putchar(' ')
    #define os(x) printf(x)
    #define all(x) x.begin(),x.end()
    #define Open() freopen("F:\rush.txt","r",stdin)
    #define Close() ios::sync_with_stdio(0)
    #define sz(x) ((int) x.size())
    #define ld long double
     
    typedef pair<int, int> pii;
    typedef pair<LL, LL> pll;
     
    //mt19937 myrand(time(0));
    //int get_rand(int n){return myrand()%n + 1;}
    const int dx[9] = { 0,1,-1,0,0,-1,-1,1,1 };
    const int dy[9] = { 0,0,0,-1,1,-1,1,-1,1 };
    const double pi = acos(-1.0);
    const int N = 10;
    const int goal = 123456789;
     
    char s[N];
    int temp,a[4][4];
    queue <int> dl;
    map <int, int> dic;
     
    int getnum(int a[4][4]) {
        int now = 0;
        rep1(i, 1, 3)
            rep1(j, 1, 3)
                now = now * 10 + a[i][j];
        return now;
    }
     
    int main() {
        //Open();
        //Close();
        while (~rs(s)) {
            int len = strlen(s);
            temp = 0;
            rep1(i, 0, len - 1)
                temp = temp * 10 + s[i] - '0';
            dic.clear();
            dl.push(temp);
            dic[temp] = 1;
            while (!dl.empty()) {
                int x = dl.front();
                int xx = x;
                dl.pop();
                if (dic[xx] >= 6) continue;
                rep2(i, 3, 1)
                    rep2(j, 3, 1) {
                    a[i][j] = x % 10;
                    x /= 10;
                    }
     
                rep1(i, 1, 3) {
                    rep1(j, 1, 3) {
                        int temp = a[i][1];
                        rep1(k, 1, 2)
                            a[i][k] = a[i][k + 1];
                        a[i][3] = temp;
                        if (j == 3) continue;
                        temp = getnum(a);
                        if (dic[temp] == 0) {
                            dic[temp] = dic[xx] + 1;
                            dl.push(temp);
                        }
                    }
                }
     
                rep1(i, 1, 3) {
                    rep1(j, 1, 3) {
                        int temp = a[1][i];
                        rep1(k, 1, 2)
                            a[k][i] = a[k + 1][i];
                        a[3][i] = temp;
                        if (j == 3) continue;
                        temp = getnum(a);
                        if (dic[temp] == 0) {
                            dic[temp] = dic[xx] + 1;
                            dl.push(temp);
                        }
                    }
                }
            }
            if (dic[goal] == 0) {
                puts("impossible");
            }
            else {
                oi(dic[goal] - 1); puts("");
            }
        }
        return 0;
    }


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  • 原文地址:https://www.cnblogs.com/AWCXV/p/7626055.html
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