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  • 树状数组 || JZOI 1024. @szefany 的树

    题面:无

    题解:无

    代码:

     1 #include<cstdio>
     2 #include<cstring>
     3 #include<iostream>
     4 #include<algorithm>
     5 using namespace std;
     6 const int maxn=(1e5)+50;
     7 int N,T,u,v,num_edge,edge_head[maxn],lsh_cnt,belong[maxn],tr[maxn],Ans[maxn];
     8 //记住树状数组里不可以塞0 
     9 //tr中的数会在回溯时删掉,所以不用清空tr 
    10 struct Edge{int to,nx;}edge[maxn<<1];
    11 inline void Add_edge(int from,int to){
    12     edge[++num_edge].nx=edge_head[from];
    13     edge[num_edge].to=to;
    14     edge_head[from]=num_edge;
    15     return;
    16 }
    17 struct Nd{int yw,w,id;}nd[maxn];
    18 inline bool cmp(const Nd&a,const Nd&b){return a.yw<b.yw;}
    19 inline void Add(int s,int x){
    20     for(int i=s;i>0;i-=i&(-i))tr[i]+=x;
    21     return;
    22 }
    23 inline int Find(int s){
    24     int ans=0;
    25     for(int i=s;i<=lsh_cnt;i+=i&(-i))ans+=tr[i];
    26     return ans;
    27 }
    28 inline void Dfs(int x,int f){
    29     for(int i=edge_head[x];i;i=edge[i].nx){
    30         int y=edge[i].to;
    31         if(y!=f){
    32             Add(nd[belong[x]].w,1);
    33             Dfs(y,x);
    34             Add(nd[belong[x]].w,-1);
    35         }
    36     }
    37     Ans[x]=Find(nd[belong[x]].w+1);
    38     return;
    39 }
    40 int main(){
    41     scanf("%d",&T);
    42     while(T--){
    43         num_edge=lsh_cnt=0;
    44         memset(edge_head,0,sizeof(edge_head));
    45         scanf("%d",&N);
    46         for(int i=1;i<N;i++){
    47             scanf("%d%d",&u,&v);
    48             Add_edge(u,v);
    49             Add_edge(v,u);
    50         }
    51         for(int i=1;i<=N;i++){
    52             scanf("%d",&nd[i].yw);
    53             nd[i].id=i;
    54         }
    55         sort(nd+1,nd+N+1,cmp);
    56         nd[1].w=++lsh_cnt;
    57         belong[nd[1].id]=1;
    58         for(int i=2;i<=N;i++){
    59             if(nd[i].yw!=nd[i-1].yw)lsh_cnt++;
    60             nd[i].w=lsh_cnt;
    61             belong[nd[i].id]=i;
    62         }
    63         Dfs(1,0);
    64         for(int i=1;i<=N;i++)printf("%d
    ",Ans[i]);
    65     }
    66     return 0;
    67 }

    By:AlenaNuna

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  • 原文地址:https://www.cnblogs.com/AlenaNuna/p/10730584.html
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