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  • 求解图的割点与桥

    割点与桥详解地址
    时间复杂度(|E| + |V|)
    板子

    int edge[MAXN][MAXN];
    int bridge[MAXN][MAXN], cut[MAXN];
    int low[MAXN], dfn[MAXN], vis[MAXN];
    int ans;
    
    
    
    void cut_bridge(int cur, int father, int dep, int n) {
        vis[cur] = 1;
        dfn[cur] = low[cur] = dep;
        int children = 0;
        for (int i = 0; i < n; i++) {
            if (edge[cur][i]) {
                if (i != father && 1 == vis[i]) {
                    if (dfn[i] < low[cur]) {
                        low[cur] = dfn[i];
                    }
                } else if (0 == vis[i]) {
                    cut_bridge(i, cur, dep+1, n);
                    children++;
                    if (low[i] < low[cur]) {
                        low[cur] = low[i];
                    }
                    if ((father == -1 && children > 1) || (father != -1 && low[i] >= dfn[cur])) {
                        cut[cur] = true;
                    }
                    if (low[i] > dfn[cur]) {
                        bridge[cur][i] = bridge[i][cur] = true;
                    }
                }
            }
        }
        vis[cur] = 2;
    }
    
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  • 原文地址:https://www.cnblogs.com/Alessandro/p/9693054.html
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