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  • RabbitMQ之RPC(Remote procedure call )

     RPC(远程过程调用)

      解决的问题:之前的模式都是基于一对一的发,另外端收到,不能继续发。

      使用多个队列对多个消费者之间分配耗时的任务

      

     客服端

     1 #!/usr/bin/env python
     2 # -*- coding:utf-8 -*-
     3 
     4 import pika
     5 import uuid
     6 
     7 
     8 class FibonacciRpcClient(object):
     9 
    10     def __init__(self):
    11         self.credentials = pika.PlainCredentials('admin', 'admin123456')
    12         self.connection = pika.BlockingConnection(pika.ConnectionParameters(host='192.168.1.6', credentials=self.credentials))
    13         self.channel = self.connection.channel()
    14 
    15         result = self.channel.queue_declare(queue='', exclusive=True)
    16         self.callback_queue = result.method.queue
    17 
    18         self.channel.basic_consume(
    19             queue=self.callback_queue,
    20             on_message_callback=self.on_response,
    21             auto_ack=True)
    22 
    23     def on_response(self, ch, method, props, body):
    24         if self.corr_id == props.correlation_id:
    25             self.response = body
    26 
    27     def call(self, n):
    28         self.response = None
    29         self.corr_id = str(uuid.uuid4())   # 唯一标识 发的消息标个记号 然后服务端处理之后才能一一对应
    30         self.channel.basic_publish(
    31             exchange='',
    32             routing_key='rpc_queue',  # 服务端生成的rpc_queue
    33             properties=pika.BasicProperties(
    34                 reply_to=self.callback_queue,  # 客服端申明回调queue
    35                 correlation_id=self.corr_id,   # 唯一值  服务端收到请求,在响应的时候,不清楚属于哪个请求的
    36             ),
    37             body=str(n))
    38         count = 0
    39         while self.response is None:
    40             # 一直循环检测 并且在这里不会阻塞
    41             self.connection.process_data_events()
    42             count += 1
    43             print(".......select.....", count)
    44         return int(self.response)
    45 
    46 
    47 fibonacci_rpc = FibonacciRpcClient()
    48 
    49 print(" [x] Requesting fib(5)")
    50 response = fibonacci_rpc.call(5)
    51 print(" [.] Got %r" % response)

    服务端

     1 #!/usr/bin/env python
     2 # -*- coding:utf-8 -*-
     3 
     4 import pika
     5 
     6 credentials = pika.PlainCredentials('admin', 'admin123456')
     7 connection = pika.BlockingConnection(pika.ConnectionParameters(host='192.168.1.6', credentials=credentials))
     8 channel = connection.channel()
     9 
    10 channel.queue_declare(queue='rpc_queue')
    11 
    12 
    13 def fib(n):
    14     if n == 0:
    15         return 0
    16     elif n == 1:
    17         return 1
    18     else:
    19         return fib(n - 1) + fib(n - 2)
    20 
    21 
    22 def on_request(ch, method, props, body):
    23     n = int(body)
    24 
    25     print(" [.] fib(%s)" % n)
    26     response = fib(n)
    27 
    28     ch.basic_publish(exchange='',
    29                      routing_key=props.reply_to,
    30                      properties=pika.BasicProperties(correlation_id = 
    31                                                          props.correlation_id),
    32                      body=str(response))
    33     ch.basic_ack(delivery_tag=method.delivery_tag)
    34 
    35 
    36 channel.basic_qos(prefetch_count=1)  # 根据任务处理能力,如果客服端处理不过来,那么就不会取任务继续处理
    37 channel.basic_consume(queue='rpc_queue', on_message_callback=on_request)
    38 
    39 print(" [x] Awaiting RPC requests")
    40 channel.start_consuming()

    运行结果:

     1 D:pythonpython.exe F:/abc/messagequeue/rpc_client.py
     2  [x] Requesting fib(5)
     3 .......select..... 1
     4 .......select..... 2
     5 .......select..... 3
     6 .......select..... 4
     7 .......select..... 5
     8 .......select..... 6
     9 .......select..... 7
    10 .......select..... 8
    11 .......select..... 9
    12 .......select..... 10
    13 .......select..... 11
    14 .......select..... 12
    15 .......select..... 13
    16 .......select..... 14
    17 .......select..... 15
    18 .......select..... 16
    19 .......select..... 17
    20 .......select..... 18
    21 .......select..... 19
    22 .......select..... 20
    23 .......select..... 21
    24 .......select..... 22
    25 .......select..... 23
    26 .......select..... 24
    27 .......select..... 25
    28 .......select..... 26
    29 .......select..... 27
    30 .......select..... 28
    31  [.] Got 5
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  • 原文地址:https://www.cnblogs.com/Alexephor/p/11579565.html
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