zoukankan      html  css  js  c++  java
  • [Functional Programming] Combine Multiple State ADT Instances with the Same Input (converge(liftA2(constant)))

    When combining multiple State ADT instances that depend on the same input, using chain can become quite burdensome. We end up having to play leapfrog with values inside of nested chain statements. Very reminiscent of the old callback nastiness we had to deal with before Promisesgraced our existence.

    But fear not, but taking advantage of the Applicative Functor portion of the State ADT in combination with the converge combinator, we can apply these types of transitions in unison, passing the value to both virtually simultaneously.

    For example:

    // () -> b
    const validateAnswer = converge(
        liftA2(equals),
        cardToHint,
        getHint
    )

    'validateAnswer' return a boolean value.

    We want to take this value, and pass to two functions 'setIsCorrect' & 'updateRank'

    // b -> ()
    const setIsCorrect = b => over('isCorrect', constant(b));
    
    // b -> ()
    const updateRank = b => over('rank', adjustRank(b));

    One functional way to do this is using 'converge':

    const applyFeedback = converge(
        liftA2(constant),
        setIsCorrect,
        updateRank
    )

    ----------------

    const {prop, State, omit, curry, converge,map, composeK, liftA2, equals, constant,option, chain, mapProps, find, propEq, isNumber, compose, safe} = require('crocks');
    const  {get, modify, of} = State; 
    
    const state = {
        cards: [
            {id: 'green-square', color: 'green', shape: 'square'},
            {id: 'orange-square', color: 'orange', shape: 'square'},
            {id: 'blue-triangle', color: 'blue', shape: 'triangle'}
        ],
        hint: {
            color: 'green',
            shape: 'square'
        },
        isCorrect: null,
        rank: 2
    }
    
    const inc = x => x + 1;
    const dec = x => x - 1;
    const incOrDec = b => b ? dec :  inc;
    const clamp = (min, max) => x => Math.min(Math.max(min, x), max);
    const clampAfter = curry((min, max, fn) => compose(clamp(min, max), fn));
    const limitRank = clampAfter(0, 4);
    const over = (key, fn) => modify(mapProps({[key]: fn}))
    const getState = key => get(prop(key));
    const liftState = fn => compose(
        of,
        fn
    )
    const getCard = id => getState('cards')
        .map(chain(find(propEq('id', id))))
        .map(option({}))
    const getHint = () => getState('hint')
        .map(option({}))
    const cardToHint = composeK(
        liftState(omit(['id'])),
        getCard
    )
    // () -> b
    const validateAnswer = converge(
        liftA2(equals),
        cardToHint,
        getHint
    )
    // b -> ()
    const setIsCorrect = b => over('isCorrect', constant(b));
    
    const adjustRank = compose(limitRank, incOrDec);
    // b -> ()
    const updateRank = b => over('rank', adjustRank(b));
    
    const applyFeedback = converge(
        liftA2(constant),
        setIsCorrect,
        updateRank
    )
    
    const feedback = composeK(
        applyFeedback,
        validateAnswer
    )
    
    console.log(
        feedback('green-square')
            .execWith(state)
    )
  • 相关阅读:
    资料-Java基础:多线程--创建启动线程的多种方式
    资料-Java基础:基础总结-运算符
    资料-Java基础:父子类加载过程
    总结提纲-逐渐补充
    资料-Java基础:类加载处理过程
    资料-Java基础:双亲委派模型
    资料-Java基础:类加载方式及差异
    转载:java 泛型详解-绝对是对泛型方法讲解最详细的,没有之一
    无法启动IIS Express web服务,端口正在使用!
    关于在本地新建数据库作业,无法成功的问题【本地SQLSERVER链接的服务器数据库】
  • 原文地址:https://www.cnblogs.com/Answer1215/p/10268647.html
Copyright © 2011-2022 走看看