Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
Example:
Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4
Solution 1:
var mergeTwoLists = function(l1, l2) { if (!l1 && !l2) { return null; } if (!l1 && l2) { return l2; } if (!l2 && l1) { return l1; } const smallerNode = l1.val <= l2.val ? l1 : l2; if (smallerNode.val === l1.val) { smallerNode.next = mergeTwoLists(l1.next, l2); } else { smallerNode.next = mergeTwoLists(l1, l2.next); } return smallerNode;
}
Solution 2: Better
/** * Definition for singly-linked list. * function ListNode(val) { * this.val = val; * this.next = null; * } */ /** * @param {ListNode} l1 * @param {ListNode} l2 * @return {ListNode} */ var mergeTwoLists = function(l1, l2) { let curr = temp = new ListNode(0) while (l1 && l2) { if (l1.val < l2.val) { curr.next = l1; l1 = l1.next; } else { curr.next = l2; l2 = l2.next; } curr = curr.next; } if (l1) { curr.next = l1; } if (l2) { curr.next = l2; } return temp.next; };