zoukankan      html  css  js  c++  java
  • [JS Compose] 1. Refactor imperative code to a single composed expression using Box

    After understanding how Box is, then we are going to see how to use Box to refacotr code, to un-nested expression.

    For example, we have code:

    const moneyToFloat = str => {
      const cost = str.replace(/$/g, '');
      return parseFloat(cost);
    }
    
    const percentToFloat = str => {
      const cost = parseFloat(str.replace(/$/g, ''));return cost * 0.01;
    }
    
    const applyDiscount = (price, prec) => {
      const cost = moneyToFloat(price);
      const p = percentToFloat(prec);
      return cost - cost * p;
    }
    
    const result = applyDiscount('$5.00', '20%')
    console.log(result) // 4

    So how it would be when we using Box version:

    const moneyToFloat = str => {
      const cost = str.replace(/$/g, '');
      return parseFloat(cost);
    }
    
    const moneyToFloat = str => 
      Box(str)
      .map(s => s.replace(/$/g, ''))
      .map(s => parseFloat(cost))

    Well, nothing really impress here, we put 'str' into Box, and using map to do all the logic.

    const percentToFloat = str => {
      const cost = parseFloat(str.replace(/$/g, ''));
      return cost * 0.01;
    }
    
    const percentToFloat = str => 
      Box(str.replace(/$/g, ''))
        .map(s => parseFloat(s))
        .map(s => s * 0.01)

    This part, notice we un-nest 'parseFloat(str.replace(...))', make logic more readable by using map.

    const applyDiscount = (price, prec) => {
      const cost = moneyToFloat(price);
      const p = percentToFloat(prec);
      return cost - cost * p;
    }
    
    const applyDiscount = (price, prec) =>
      moneyToFloat(price)
        .fold(cost => percentToFloat(prec)
             .fold(p => cost - cost * p))

    Notice here, because 'moneyToFloat' return a Box, so we are able to chain map on that.

    And 'cost', we can use clouse to remember 'cost', and chain 'fold' on precentToFloat. The reason we use 'fold' instead of 'map', is 'fold' we can get value out of Box.

    const Box = x =>
    ({
      map: f => Box(f(x)),
      fold: f => f(x),
      toString: () => `Box(${x})`
    })
    
    const moneyToFloat = str => 
      Box(str)
      .map(s => s.replace(/$/g, ''))
      .map(s => parseFloat(cost));
    
    const percentToFloat = str => 
      Box(str.replace(/$/g, ''))
        .map(s => parseFloat(s))
        .map(s => s * 0.01);
    
    const applyDiscount = (price, prec) =>
      moneyToFloat(price)
        .fold(cost => percentToFloat(prec)
             .fold(p => cost - cost * p))
    
    const result = applyDiscount('$5.00', '20%')
    console.log(result) // 4
  • 相关阅读:
    Oracle SQL 函数
    j2me MIDP2.0 下实现split函数
    Linux Oracle 增量恢复时错误 ORA19573: 无法获得 exclusive 入队 (数据文件 5 的)
    Linux Oracle10 建立归档模式的详细过程
    j2me MIDP2.0 下实现的图片缩放函数
    linux下oracle10g建立归档模式 接连出现错误:ORA19905 ORA01078 LRM00109
    j2me下 触摸屏的开发 NetBeans 模拟器支持触摸屏
    高级程序员:你不可不知的20条编程经验(转载)
    生成规定大小的图片(缩略图生成)
    asp.net简单实现用button做按钮图片
  • 原文地址:https://www.cnblogs.com/Answer1215/p/6161182.html
Copyright © 2011-2022 走看看