zoukankan      html  css  js  c++  java
  • [Redux] Understand Redux Higher Order Reducers

    Higher Order Reducers are simple reducer factories, that take a reducer as an argument and return a new reducer. In that new reducer, you can customize the behaviour of the original one which helps reducing the reducer logic.

    In this lesson, we'll see how to reduce duplicated code by refactoring two different reducers into a higher order reducer.

     

    Reducers:

    export default (state = [], { type, payload }) => {
      switch (type) {
         case "ADD_ARTICLE":
           return [...state, payload]
    
        default:
          return state
      }
    }
    export default (state = [], { type, payload }) => {
      switch (type) {
         case "ADD_USER":
           return [...state, payload]
    
        default:
          return state
      }
    }

    They both share the same code structure.

    HOC reducer:

    which is a reducer hoc function return a reducer function.

    import { combineReducers } from "redux"
    import users from "./users"
    import articles from "./articles"
    
    const addHoc = (reducer, predicate) => (state, action) => {
      if (predicate(action.type)) {
        return [...state, action.payload]
      }
      return reducer(state, action)
    }
    
    const rootReducer = combineReducers({
      users: addHoc(users, type => type === "ADD_USER"),
      articles: addHoc(articles, type => type === "ADD_ARTICLE")
    })
    
    export default rootReducer

    If match the predicate function, then we can compute the next state and return it. If doesn't match, then pass to the reducer normally. Then we can remove "ADD_USER" and "ADD_ARTICLE" cases from reducers.

    Personally I don't think this is a good approach... even it reduce the boilerplate code, but it decrease the code readability. I still prefer keep all the reducer logic inside the its reducer file. Just make a reuseable function would be better:

    export const append = (state, payload) => {
      return [...state, payload]
    }
    
    
    export default (state = [], { type, payload }) => {
      switch (type) {
         case "ADD_USER":
           return append(state, payload)
    
        default:
          return state
      }
    }

     It also make Unit testings easier.

  • 相关阅读:
    sqlserver判断是否为数字的函数
    vs2013 旗舰版 密钥
    HttpWebRequest类与HttpRequest类的区别
    C#中HttpWebRequest的用法详解
    SQL Server查询优化方法(查询速度慢的原因很多,常见如下几种)
    随机数Random
    PadLeft 补零
    delphi Firemonkey ListBoxItem自绘
    windows自带杀毒防火墙
    IIS 更新EXE文件
  • 原文地址:https://www.cnblogs.com/Answer1215/p/7524321.html
Copyright © 2011-2022 走看看