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  • [Leetcode] Binary Tree Postorder Traversal

    Problem statement:

    Thought: Since TreeNode has a self-recursive structure, it's very natural and easy to come up with a recursive implement. But the tricky part is how to implement this using a iterative method. The three binary tree traversal methods: pre-order, in-order and post-order can all be regarded as Depth First Search, and we know the iterative version of DFS makes use of a stack. So maybe we can also use a stack to solve this problem.

    Because this problem is postorder, the relative position of node, left subtree, right subtree should be like this:

    In-order traversal is similar, siwtching position of Right and Node in the above picture.

    Pre-order is the simplest of three, just run iterative-DFS on the root node.

    public class Binary_tree_postorder_traversal {
    
        public ArrayList<Integer> postorderTraversal(TreeNode root) {
            ArrayList<Integer> list = new ArrayList<Integer>();
            if(root == null){
                return list;
            }
            
            Stack<StatusNode> stack = new Stack<StatusNode>();
            stack.push(new StatusNode(root, true));
            stack.push(new StatusNode(root.right, false));
            stack.push(new StatusNode(root.left, false));
            
            while(!stack.isEmpty()){
                StatusNode node = stack.peek();
                if(node.internalNode == null){
                    stack.pop();
                    continue;
                }
                if(node.finished){
                    list.add(stack.pop().internalNode.val);
                    
                }else{
                    stack.push(new StatusNode(node.internalNode.right, false));
                    stack.push(new StatusNode(node.internalNode.left, false));
                    node.finished = true;
                }
            }
            return list;
        }
    
    }
    
    
    class StatusNode{
        boolean finished;// if true, just output it, otherwise expand it
        TreeNode internalNode;
        
        public StatusNode(TreeNode node, boolean finished){
            this.internalNode = node;
            this.finished = finished;
        }
    }
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  • 原文地址:https://www.cnblogs.com/Antech/p/3655594.html
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