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  • 一般图极大团个数,最大团顶点数

    极大团个数:POJ 2989

    #include <cstdio>
    #include <cstring>
    using namespace std;
    const int maxn = 130;
    bool mp[maxn][maxn];
    int some[maxn][maxn], none[maxn][maxn], all[maxn][maxn];
    int n, m, ans;
    void dfs(int d, int an, int sn, int nn)
    {
        if(!sn && !nn) ++ans;
        int u = some[d][0];
        for(int i = 0; i < sn; ++i)
        {
            int v = some[d][i];
            if(mp[u][v]) continue;
            for(int j = 0; j < an; ++j)
            all[d+1][j] = all[d][j];
            all[d+1][an] = v;
            int tsn = 0, tnn = 0;
            for(int j = 0; j < sn; ++j)
            if(mp[v][some[d][j]])
            some[d+1][tsn++] = some[d][j];
            for(int j = 0; j < nn; ++j)
            if(mp[v][none[d][j]])
            none[d+1][tnn++] = none[d][j];
            dfs(d+1, an+1, tsn, tnn);
            some[d][i] = 0, none[d][nn++] = v;
        }
    }
    int work()
    {
        ans = 0;
        for(int i = 0; i < n; ++i) some[1][i] = i+1;
        dfs(1, 0, n, 0);
        return ans;
    }
    int main()
    {
        while(~scanf("%d %d", &n, &m))
        {
            memset(mp, 0, sizeof mp);
            for(int i = 1; i <= m; ++i)
            {
                int u, v;
                scanf("%d %d", &u, &v);
                mp[u][v] = mp[v][u] = 1;
            }
            int tmp = work();
            printf("%d
    ", tmp);
        }
        return 0;
    }
    View Code

    最大团顶点数:ZOJ 1492

    #include <bits/stdc++.h>
    using namespace std;
    const int maxn = 55;
    bool mp[maxn][maxn];
    int best, n, num[maxn];
    bool dfs(int *adj, int total, int cnt)
    {
        int t[maxn], k;
        if (total == 0) {
            if (cnt > best) {
                best = cnt;
                return true;    //剪枝4
            }
            return false;
        }
        for (int i = 0; i < total; ++i) {
            if (cnt + total - i <= best) {
                return false;    //剪枝1
            }
            if (cnt + num[adj[i]] <= best) {
                return false;    //剪枝3
            }
            k = 0;
            for (int j = i + 1; j < total; ++j)
                if (mp[adj[i]][adj[j]]) {
                    t[k++] = adj[j];
                }
            //扫描与u相连的顶点中与当前要选中的adj[i]相连的顶点adj[j]并存储到数组t[]中,数量为k
            if (dfs(t, k, cnt + 1)) {
                return true;
            }
        }
        return false;
    }
    int MaximumClique()
    {
        int adj[maxn], k;
        best = 0;
        for (int i = n; i >= 1; --i) {
            k = 0;
            for (int j = i + 1; j <= n; ++j)
                if (mp[i][j]) {
                    adj[k++] = j;
                }
            //得到当前点i的所有相邻点存入adj
            dfs(adj, k, 1); //每次dfs相当于必选当前i点看是否能更新best
            num[i] = best;
        }
        return best;
    }
    int main()
    {
        while (scanf("%d", &n) != -1 && n) {
            for (int i = 1; i <= n; ++i)
                for (int j = 1; j <= n; ++j) {
                    scanf("%d", &mp[i][j]);
                }
            printf("%d
    ", MaximumClique());
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/Aragaki/p/9918003.html
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