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  • 【LeetCode】051. N-Queens

    题目:

    The n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other.

    Given an integer n, return all distinct solutions to the n-queens puzzle.

    Each solution contains a distinct board configuration of the n-queens' placement, where 'Q' and '.' both indicate a queen and an empty space respectively.

    For example,
    There exist two distinct solutions to the 4-queens puzzle:

    [
     [".Q..",  // Solution 1
      "...Q",
      "Q...",
      "..Q."],
    
     ["..Q.",  // Solution 2
      "Q...",
      "...Q",
      ".Q.."]
    ]
    

      

    题解:

    class Solution {
    public:
        void dfs(vector<vector<string>>& res, vector<string>& v, int n, vector<int>& pos, int row) {
             if(row >= n) {
                 res.push_back(v);
                 return;
             }
             for(int col=0; col<n; ++col) {
                if (!isValid(pos, row, col)) {
                    continue;
                }
                v[row][col] = 'Q';
                pos[row] = col;
                dfs(res, v, n, pos, row + 1);
                pos[row] = -1;
                v[row][col] = '.';
             }
        }
        bool isValid(vector<int>& pos, int row, int col) {
            for (int i = 0; i < row; ++i) {
                if (pos[i] == col || abs(row - i) == abs(col - pos[i])) {
                    return false; 
                }
            }
            return true;
        }
        vector<vector<string>> solveNQueens(int n) {
            vector<vector<string>> res;
            vector<string> v(n, string(n, '.'));
            vector<int> pos(n, -1);
            dfs(res, v, n, pos, 0);
            return res;        
        }
    };
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  • 原文地址:https://www.cnblogs.com/Atanisi/p/6791229.html
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