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  • UVA 11525 Permutation 康拓展开

    //#pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<cstdio>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    #include<iostream>
    #include<sstream>
    #include<cmath>
    #include<climits>
    #include<string>
    #include<map>
    #include<queue>
    #include<vector>
    #include<stack>
    #include<set>
    using namespace std;
    typedef long long ll;
    typedef pair<int,int> pii;
    #define pb(a) push_back(a)
    #define INF 0x1f1f1f1f
    #define lson idx<<1,l,mid
    #define rson idx<<1|1,mid+1,r
    #define PI  3.1415926535898
    template<class T> T min(const T& a,const T& b,const T& c) {
        return min(min(a,b),min(a,c));
    }
    template<class T> T max(const T& a,const T& b,const T& c) {
        return max(max(a,b),max(a,c));
    }
    void debug() {
    #ifdef ONLINE_JUDGE
    #else
    
        freopen("d:\in.txt","r",stdin);
       // freopen("d:\out1.txt","w",stdout);
    #endif
    }
    int getch() {
        int ch;
        while((ch=getchar())!=EOF) {
            if(ch!=' '&&ch!='
    ')return ch;
        }
        return EOF;
    }
    const int maxn=55555;
    int sum[maxn<<2];
    int build(int idx,int l,int r)
    {
        sum[idx]=r-l+1;
        if(l==r)return 0;
        int mid=(r+l)>>1;
        build(lson);
        build(rson);
        return 0;
    }
    int query(int idx,int l,int r,int v,int &pos)
    {
        if(l==r)
        {
            pos=l;
        }else
        {
            int mid=(r+l)>>1;
            if(sum[idx<<1]>=v)query(lson,v,pos);
            else query(rson,v-sum[idx<<1],pos);
        }
        sum[idx]--;
        return 0;
    }
    
    int ans[maxn];
    int main()
    {
        int t;
        scanf("%d",&t);
        for(int ca=1;ca<=t;ca++)
        {
            int k;
            scanf("%d",&k);
            build(1,1,k);
            for(int K=1;K<=k;K++)
            {
                int s,pos;
                scanf("%d",&s);
                query(1,1,k,s+1,pos);
                ans[K]=pos;
            }
            for(int i=1;i<=k;i++)
                printf("%d%c",ans[i],i==k?'
    ':' ');
    
        }
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/BMan/p/3359098.html
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