zoukankan      html  css  js  c++  java
  • SQL16进制2进制,10进制(转)

    16进制2进制,10进制
     

    /*===============
      --将16进制数据初步转化为2进制
      --created by h11h99
    create function HToT(@str char(1))
    returns varchar(4)
    as
    begin
    declare @var varchar(8000)
    set @var=case
    when @str='0' then '0000'
    when @str='1' then '0001'
    when @str='2' then '0010'
    when @str='3' then '0011'
    when @str='4' then '0100'
    when @str='5' then '0101'
    when @str='6' then '0110'
    when @str='7' then '0111'
    when @str='8' then '1000'
    when @str='9' then '1001'
    when @str='A' then '1010'
    when @str='B' then '1011'
    when @str='C' then '1100'
    when @str='D' then '1101'
    when @str='E' then '1110'
    when @str='F' then '1111'
    end
    return @var
    end
    */
    /* 将长字符串转化为每四位一行 */
    declare  @string varchar(8000)
    declare  @i int
    declare  @table table(id int,content varchar(10))
    set @string='0EEA680031003100680039003900'
    set @i=1
    while (@i<=len(@string)/4)
    begin
    set @string=replace(@string,char(10),'')
    set @string=replace(@string,char(13),'')
    insert into @table(id,content) values(@i,substring(@string,(@i-1)*4+1,4))
    set @i=@i+1
    end
    update @table set content=right(content,2)+left(content,2)
    select *  from @table
    /*
    结果
    1 EA0E
    2 0068
    3 0031
    4 0031
    5 0068
    6 0039
    7 0039
    */
    /* 将16进制转化为2进制 */
    declare @str varchar(20)
    declare @res varchar(20)
    declare @i int
    set @i=1
    set @str='0039'
    set @res=''
    while @i<5
    begin
    set @res=@res+dbo.HToT(substring(@str,@i,1))
    set @i=@i+1
    end
    select @res '十六进制对应的二进制为'

    /*
    结果
    EA0E:1110101000001110
    0068:0000000001101000
    0031:0000000000110001
    0031:0000000000110001
    0039:0000000000111001
    0039:0000000000111001
    */
    /* 将2进制转化为10进制 */
    declare @str varchar(20)
    declare @i int
    declare @p int
    declare @sum int
    set @sum=0
    set @str='0000000000111001'
    while charindex('1',@str)<>0
    begin
    set @i=charindex('1',@str)
    set @str=stuff(@str,charindex('1',@str),1,'s')
    set @p=len(@str)-@i
    set @sum=@sum+power(2,@p)
    end
    select @sum as '二进制对应的十进制为'
    select nchar(@sum) '对应的字符为'
    /*
    结果
    EA0E:1110101000001110  59918
    0068:0000000001101000  104    h
    0031:0000000000110001  49     1
    0031:0000000000110001  49     1
    0068:0000000001101000  104    h
    0039:0000000000111001  57     9
    0039:0000000000111001  57     9
    */
    declare @b varchar(8000)
    declare @index int
    declare @times int
    declare @char varchar(10)
    declare @length int
    declare @result varchar(100)
    set @b='fffffdddzzzzaaccca'
    set @index=2
    set @times=1
    set @char=''
    set @result=''
    --set @char=''
    SET @length=len(@b)
    while @index<@length
      begin
     set @char=substring(@b,@index,1)
      if (substring(@b,@index-1,1)=substring(@b,@index,1))
      begin
      set @times=@times+1
      end
     IF @times>=3
     begin
    /*
      if charindex(@char,@result)=0
      begin
      set @result=@result+@char
      end
    */
     set @result=@result+@char
     set @times=0
     end
     set @index=@index+1
      
      end
      PRINT @result
     
    create table list (uid varchar(8),regdate datetime default getdate())
    create table t(uid varchar(8))
    insert into list(uid) values('111345')
    insert into list(uid) values('123456')
    insert into list(uid) values('122249')
    insert into list(uid) values('123444')
    create procedure gethree(@a varchar(1))
    as
    declare  @b int, @str varchar(8)
    declare cur cursor local for select uid from plat_uidlist
    begin
    open cur
    fetch next from cur into @str
    while @@fetch_status =0
    begin
    select @b=charindex(replace(@a+@a+@a,' ',''),sid) from list where uid = @str
    if @b>0
    begin
    insert into t values(@str)
    end
    fetch next from cur into @str
    end

    declare @a int
    set @a=0
    while @a<10
    begin
    exec getthree @a
    set @a=@a+1
    end
  • 相关阅读:
    一文搞懂 deconvolution、transposed convolution、sub-­pixel or fractional convolution
    Knative 实战:三步走!基于 Knative Serverless 技术实现一个短网址服务
    使用Bookinfo应用测试Kuma服务网格
    数学——Euler方法求解微分方程详解(python3)
    深度学习之卷积神经网络CNN及tensorflow代码实现示例
    如何让cxgrid既能充满又能根据内容进行宽度调整?
    cxgrid过滤使用心得
    DevExpress控件cxGrid实现多列模糊匹配输入的完美解决方案
    sqlserver的触发器练习实例
    SQL Server 创建触发器(trigger)
  • 原文地址:https://www.cnblogs.com/BloodAndBone/p/1781365.html
Copyright © 2011-2022 走看看