牛客SQL题解-将employees表的所有员工的last_name和first_name拼接起来作为Name，中间以一个空格区分

题目描述

将employees表的所有员工的last_name和first_name拼接起来作为Name，中间以一个空格区分

(注：sqllite,字符串拼接为 || 符号，不支持concat函数，mysql支持concat函数)

CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));

输入描述:

无

输出描述:

Name

Facello Georgi

Simmel Bezalel

Bamford Parto

Koblick Chirstian

Maliniak Kyoichi

Preusig Anneke

Zielinski Tzvetan

Kalloufi Saniya

Peac Sumant

Piveteau Duangkaew

Sluis Mary    

答案详解

select concat(last_name," ",first_name) as Name from employees