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  • AIM Tech Round 4 (Div. 1) C

    C - Upgrading Tree

    我发现我构造题好弱啊啊啊。

    很明显能想到先找到重心, 然后我们的目标就是把所有点接到重心的儿子上,让重心的儿子子树变成菊花图,

    这个先把重心到儿子的边连到 i , 然后把 i 到 其 fa 的边连到重心的儿子上, 一直循环就好啦。

    #include<bits/stdc++.h>
    #define LL long long
    #define fi first
    #define se second
    #define mk make_pair
    #define PLL pair<LL, LL>
    #define PLI pair<LL, int>
    #define PII pair<int, int>
    #define SZ(x) ((int)x.size())
    #define ull unsigned long long
    
    using namespace std;
    
    const int N = 2e5 + 7;
    const int inf = 0x3f3f3f3f;
    const LL INF = 0x3f3f3f3f3f3f3f3f;
    const int mod = 1e9 + 7;
    const double eps = 1e-8;
    const double PI = acos(-1);
    
    int n, last, start, who, sum[N];
    vector<int> G[N];
    vector<pair<int,PII>> ans;
    
    PII getCenter(int u, int fa) {
        PII tmp = mk(inf, u);
        sum[u] = 1;
        int mx = 0;
        for(int v : G[u]) {
            if(v == fa) continue;
            tmp = min(tmp, getCenter(v, u));
            sum[u] += sum[v];
            mx = max(mx, sum[v]);
        }
        mx = max(mx, n-sum[u]);
        return min(tmp, mk(mx, u));
    }
    
    void work(int u, int fa) {
        sum[u] = 1;
        for(int v : G[u]) if(v != fa)
            work(v, u), sum[u] += sum[v];
    }
    
    void dfs(int u, int fa) {
        if(fa != who) {
            ans.push_back(mk(who, mk(last, u)));
            ans.push_back(mk(u, mk(fa, start)));
            last = u;
        }
        for(int v : G[u])
            if(v != fa) dfs(v, u);
    }
    
    void solve(int u, int fa) {
        who = u;
        for(int v : G[u]) {
            if(v == fa) continue;
            start = v;
            last = v;
            dfs(v, u);
            ans.push_back(mk(u, mk(last, v)));
        }
    }
    
    int main() {
        scanf("%d", &n);
        for(int i = 1; i < n; i++) {
            int u, v; scanf("%d%d", &u, &v);
            G[u].push_back(v);
            G[v].push_back(u);
        }
        int root = getCenter(1, 0).se, root2 = -1;
        work(root, 0);
        for(int v : G[root])
            if(n % 2 == 0 && sum[v] == n/2)
                root2 = v;
        if(~root2) solve(root, root2), solve(root2, root);
        else solve(root, 0);
        printf("%d
    ", ans.size());
        for(auto t : ans) printf("%d %d %d
    ", t.fi, t.se.fi, t.se.se);
        return 0;
    }
    
    /*
    */
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  • 原文地址:https://www.cnblogs.com/CJLHY/p/10254485.html
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