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  • HDU

    HDU - 5411

    考虑直接dp会T, 用矩阵优化一下就好了。

    #include<bits/stdc++.h>
    #define LL long long
    #define LD long double
    #define ull unsigned long long
    #define fi first
    #define se second
    #define mk make_pair
    #define PLL pair<LL, LL>
    #define PLI pair<LL, int>
    #define PII pair<int, int>
    #define SZ(x) ((int)x.size())
    #define ALL(x) (x).begin(), (x).end()
    #define fio ios::sync_with_stdio(false); cin.tie(0);
    
    using namespace std;
    
    const int N = 50 + 2;
    const int inf = 0x3f3f3f3f;
    const LL INF = 0x3f3f3f3f3f3f3f3f;
    const int mod = 2015;
    const double eps = 1e-8;
    const double PI = acos(-1);
    
    template<class T, class S> inline void add(T &a, S b) {a += b; if(a >= mod) a -= mod;}
    template<class T, class S> inline void sub(T &a, S b) {a -= b; if(a < 0) a += mod;}
    template<class T, class S> inline bool chkmax(T &a, S b) {return a < b ? a = b, true : false;}
    template<class T, class S> inline bool chkmin(T &a, S b) {return a > b ? a = b, true : false;}
    
    mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
    
    int MN, n, m;
    
    struct Matrix {
        int a[N][N];
        Matrix() {
            for(int i = 0; i < MN; i++) {
                for(int j = 0; j < MN; j++) {
                    a[i][j] = 0;
                }
            }
        }
        void init() {
            for(int i = 0; i < MN; i++) {
                a[i][i] = 1;
            }
        }
        Matrix operator * (const Matrix &B) {
            Matrix C;
            for(int i = 0; i < MN; i++) {
                for(int j = 0; j < MN; j++) {
                    for(int k = 0; k < MN; k++) {
                        C.a[i][j] = (C.a[i][j] + a[i][k] * B.a[k][j]) % mod;
                    }
                }
            }
            return C;
        }
        Matrix operator ^ (int b) {
            Matrix A = (*this);
            Matrix C; C.init();
            while(b) {
                if(b & 1) C = C * A;
                A = A * A; b >>= 1;
            }
            return C;
        }
    } mat;
    
    int main() {
        int T; scanf("%d", &T);
        while(T--) {
            scanf("%d%d", &n, &m);
            MN = n + 1;
            for(int i = 0; i < MN; i++) {
                for(int j = 0; j < MN; j++) {
                    mat.a[i][j] = (i == MN - 1) ? 1 : 0;
                }
            }
            for(int i = 0; i < n; i++) {
                int k, x; scanf("%d", &k);
                while(k--) {
                    scanf("%d", &x);
                    mat.a[i][x - 1]++;
                }
            }
            Matrix ret = mat ^ m;
            int ans = 0;
            for(int j = 0; j < MN; j++) {
                add(ans, ret.a[MN - 1][j]);
            }
            printf("%d
    ", ans);
        }
        return 0;
    }
    
    /*
    */
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  • 原文地址:https://www.cnblogs.com/CJLHY/p/11156609.html
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