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  • POJ 1065 Wooden Sticks



    Wooden Sticks
    Time Limit: 1000MSMemory Limit: 10000K
    Total Submissions: 16262Accepted: 6748

    Description

    There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to prepare processing a stick. The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows: 
    (a) The setup time for the first wooden stick is 1 minute. 
    (b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l' and weight w' if l <= l' and w <= w'. Otherwise, it will need 1 minute for setup. 
    You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are ( 9 , 4 ) , ( 2 , 5 ) , ( 1 , 2 ) , ( 5 , 3 ) , and ( 4 , 1 ) , then the minimum setup time should be 2 minutes since there is a sequence of pairs ( 4 , 1 ) , ( 5 , 3 ) , ( 9 , 4 ) , ( 1 , 2 ) , ( 2 , 5 ) .

    Input

    The input consists of T test cases. The number of test cases (T) is given in the first line of the input file. Each test case consists of two lines: The first line has an integer n , 1 <= n <= 5000 , that represents the number of wooden sticks in the test case, and the second line contains 2n positive integers l1 , w1 , l2 , w2 ,..., ln , wn , each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one or more spaces.

    Output

    The output should contain the minimum setup time in minutes, one per line.

    Sample Input

    3
    5
    4 9 5 2 2 1 3 5 1 4
    3
    2 2 1 1 2 2
    3
    1 3 2 2 3 1

    Sample Output

    2
    1
    3

    Source




     
    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <algorithm>

    using namespace std;

    struct Node
    {
        int l;
        int w;
        int id;
    }p[5555];

    bool cmp(Node x,Node y)
    {
        if(x.l!=y.l)
        {
            return x.l<y.l;
        }
        else
        {
            return x.w<y.w;
        }
    }

    int main()
    {
        int T;
        cin>>T;
    while(T--)
    {
        memset(p,0,sizeof(p));
        int n;
        cin>>n;
        for(int i=0;i<n;i++)
        {
            cin>>p.l>>p.w;
            p.id=i;
        }

        sort(p,p+n,cmp);
        int dp[5555];

        for(int i=0;i<n;i++)
        {
            dp=1;
            for(int j=0;j<i;j++)
            {
                if(p.w<p[j].w)
                {
                    if(dp<dp[j]+1)
                    {
                        dp=dp[j]+1;
                    }
                }
            }
        }

        int maxn=-1;
        for(int i=0;i<n;i++)
        {
    //        cout<<p.id<<" ";
            maxn=max(maxn,dp);
        }
    //    cout<<endl;

        cout<<maxn<<endl;

    }
        return 0;
    }

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  • 原文地址:https://www.cnblogs.com/CKboss/p/3350992.html
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