zoukankan      html  css  js  c++  java
  • JAG Asia 2016-Similarity of Subtrees(BFS+哈希)

    Similarity of Subtrees

    时间限制: 1 Sec  内存限制: 128 MB

    题目描述

    Define the depth of a node in a rooted tree by applying the following rules recursively:
    ·The depth of a root node is 0.
    ·The depths of child nodes whose parents are with depth d are d+1.
    Let S(T,d) be the number of nodes of T with depth d. Two rooted trees T and T′ are similar if and only if S(T,d) equals S(T′,d) for all non-negative integer d.

    You are given a rooted tree T with N nodes. The nodes of T are numbered from 1 to N. Node 1 is the root node of T. Let Ti be the rooted subtree of T whose root is node i. Your task is to write a program which calculates the number of pairs (i,j) such that Ti and Tj are similar and i<j.

    输入

    The input consists of a single test case.

    N
    a1 b1
    a2 b2
    ...
    aN−1 bN−1

    The first line contains an integer N (1≤N≤100,000), which is the number of nodes in a tree. The following N−1 lines give information of branches: the i-th line of them contains ai and bi, which indicates that a node ai is a parent of a node bi. (1≤ai,bi≤N,ai≠bi) The root node is numbered by 1. It is guaranteed that a given graph is a rooted tree, i.e. there is exactly one parent for each node except the node 1, and the graph is connected.

    输出

    Print the number of the pairs (x,y) of the nodes such that the subtree with the root x and the subtree with the root y are similar and x<y.

    样例输入

    5
    1 2
    1 3
    1 4
    1 5
    

    样例输出

    6

     1 #include<bits/stdc++.h>
     2 #pragma GCC optimize(3)
     3 using namespace std;
     4 typedef long long ll;
     5 const int maxn=1e6+7;
     6 const ll prime=1e5+7;
     7 const ll mod=1e9+7;
     8 map<ll,ll>MAP;
     9 ll Hash_val[maxn];
    10 vector<int>vct[maxn];
    11 void bfs(int a)
    12 {
    13     Hash_val[a]=1;
    14     int siz=vct[a].size();
    15     for(int i=0;i<siz;++i)
    16     {
    17         int b=vct[a][i];
    18         bfs(b);
    19         Hash_val[a]=(Hash_val[a]+Hash_val[b]*prime)%mod;
    20     }
    21     MAP[Hash_val[a]]++;
    22 }
    23 int main()
    24 {
    25     int n;
    26     scanf("%d",&n);
    27     for(int i=1;i<n;++i)
    28     {
    29         int a,b;
    30         scanf("%d%d",&a,&b);
    31         vct[a].push_back(b);
    32     }
    33     ll ans=0;
    34     bfs(1);
    35     for(map<ll,ll>::iterator it=MAP.begin();it!=MAP.end();++it)
    36     {
    37         ans+=(it->second-1)*(it->second)/2;
    38     }
    39     printf("%lld
    ",ans);
    40     return 0;
    41 }
     
  • 相关阅读:
    MySQL之增_insert-replace
    Linux如何配置bond
    行转列及列转行查询
    SELECT中常用的子查询操作
    SELECT中的多表连接
    MySQL最常用分组聚合函数
    SELECT中的if_case流程函数
    MySQL常用日期时间函数
    MySQL常用数值函数
    dnslog注入
  • 原文地址:https://www.cnblogs.com/CharlieWade/p/11449036.html
Copyright © 2011-2022 走看看