Sql存储过程解密方法

在网上查到这样一个存储过程解密的方法，用起来简单，收藏到这里：

CREATE     PROCEDURE   sp_decrypt_sp   (@objectName   varchar(50))  
  AS  
  ------------------------sql2000大于40000的-----------------  
  --原作：j9988   号:J老师  
   
  begin   tran  
  begin  
  declare   @objectname1   varchar(100)  
  declare   @sql1   nvarchar(4000),@sql2   nvarchar(4000),@sql3   nvarchar(4000),@sql4   nvarchar(4000),@sql5   nvarchar(4000),@sql6   nvarchar(4000),@sql7   nvarchar(4000),@sql8   nvarchar(4000),@sql9   nvarchar(4000),@sql10   nvarchar(4000)      
  DECLARE     @OrigSpText1   nvarchar(4000),     @OrigSpText2   nvarchar(4000)   ,   @OrigSpText3   nvarchar(4000),   @resultsp   nvarchar(4000)  
  declare     @i   int   ,   @t   bigint  
  declare   @m   int,@n   int,@q   int  
  set   @m=(SELECT   max(colid)   FROM   syscomments     WHERE   id   =   object_id(@objectName))  
  set   @n=1  
  --get   encrypted   data  
  create   table     #temp(colid   int,ctext   varbinary(8000))  
  insert   #temp   SELECT   colid,ctext   FROM   syscomments     WHERE   id   =   object_id(@objectName)  
  set   @sql1='ALTER   PROCEDURE   '+   @objectName   +'   WITH   ENCRYPTION   AS   '  
  --set   @sql1='ALTER   PROCEDURE   '+   @objectName   +'   WITH   ENCRYPTION   AS   '  
  set   @q=len(@sql1)  
  set   @sql1=@sql1+REPLICATE('-',4000-@q)  
  select   @sql2=REPLICATE('-',4000),@sql3=REPLICATE('-',4000),@sql4=REPLICATE('-',4000),@sql5=REPLICATE('-',4000),@sql6=REPLICATE('-',4000),@sql7=REPLICATE('-',4000),@sql8=REPLICATE('-',4000),@sql9=REPLICATE('-',4000),@sql10=REPLICATE('-',4000)  
  exec(@sql1+@sql2+@sql3+@sql4+@sql5+@sql6+@sql7+@sql8+@sql9+@sql10)  
  while   @n<=@m  
  begin  
  SET   @OrigSpText1=(SELECT   ctext   FROM   #temp     WHERE   colid=@n)  
  set   @objectname1=@objectname+'_t'  
  SET   @OrigSpText3=(SELECT   ctext   FROM   syscomments   WHERE   id=object_id(@objectName)   and   colid=@n)  
  if   @n=1  
  begin  
  SET   @OrigSpText2='CREATE   PROCEDURE   '+   @objectName   +'   WITH   ENCRYPTION   AS   '--  
  set   @q=4000-len(@OrigSpText2)  
  set   @OrigSpText2=@OrigSpText2+REPLICATE('-',@q)  
  end  
  else  
  begin  
  SET   @OrigSpText2=REPLICATE('-',   4000)  
  end  
  --start   counter  
  SET   @i=1  
  --fill   temporary   variable  
  SET   @resultsp   =   replicate(N'A',   (datalength(@OrigSpText1)   /   2))  
   
  --loop  
  WHILE   @i<=datalength(@OrigSpText1)/2  
  BEGIN  
  --reverse   encryption   (XOR   original+bogus+bogus   encrypted)  
  SET   @resultsp   =   stuff(@resultsp,   @i,   1,   NCHAR(UNICODE(substring(@OrigSpText1,   @i,   1))   ^  
                                                                  (UNICODE(substring(@OrigSpText2,   @i,   1))   ^  
                                                                  UNICODE(substring(@OrigSpText3,   @i,   1)))))  
          SET   @i=@i+1  
  END  
  --drop   original   SP  
  --EXECUTE   ('drop   PROCEDURE   '+   @objectName)  
  --remove   encryption  
  --preserve   case  
  SET   @resultsp=REPLACE((@resultsp),'WITH   ENCRYPTION',   '')  
  SET   @resultsp=REPLACE((@resultsp),'With   Encryption',   '')  
  SET   @resultsp=REPLACE((@resultsp),'with   encryption',   '')  
  IF   CHARINDEX('WITH   ENCRYPTION',UPPER(@resultsp)   )>0    
      SET   @resultsp=REPLACE(UPPER(@resultsp),'WITH   ENCRYPTION',   '')  
  --replace   Stored   procedure   without   enryption  
  print   @resultsp  
  --execute(   @resultsp)  
  set   @n=@n+1  
  end  
  drop   table   #temp  
  end  
  rollback   tran  
  --适合40000字符。  
  --每次4000　print出来，自已贴。  
  --切记：我见过的解过程都是对原过程进行破坏。破解前一定要备份!!!!  
  --超过40000的，自已加SQL（我上面用SQL.SQL2－－SQL10）  
  --超长的可加SQL11--sql20........  
   
   
  GO