Spring整合CXF发布及调用WebService

这几天终于把webService搞定,下面给大家分享一下发布webService和调用webService的方法

1. 添加jar包 (官方下载地址:http://cxf.apache.org/download.html 为了方便扩展我把所有的jar包都加了)
2. 在web.xml中配置spirng以及CXF

   <?xml version="1.0" encoding="UTF-8"?>
   <web-app version="2.5" 
       xmlns="http://java.sun.com/xml/ns/javaee" 
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
       xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
       http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
     <display-name></display-name>    
     <welcome-file-list>
       <welcome-file>index.jsp</welcome-file>
     </welcome-file-list>
     <!-- spring -->
     <context-param>
         <param-name>contextConfigLocation</param-name>
         <param-value>classpath:applicationContext.xml</param-value>
     </context-param>
     
     <listener>
       <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
     </listener>
     
     
     <listener>
         <listener-class>org.springframework.web.util.IntrospectorCleanupListener</listener-class>
     </listener>
     
       <!-- CXFService -->
       <servlet>
           <servlet-name>CXFService</servlet-name>
           <servlet-class>org.apache.cxf.transport.servlet.CXFServlet</servlet-class>
       </servlet>
       
       <servlet-mapping>
           <servlet-name>CXFService</servlet-name>
           <url-pattern>/*</url-pattern>
       </servlet-mapping>
   </web-app>

   3.写接口实现类   要发布webService的类及要被调用的接口

   package cn.com.lrl.service.impl;
   
   import javax.jws.WebParam;
   import javax.jws.WebResult;
   import javax.jws.WebService;
   
   import cn.com.lrl.service.JAXService;
   @WebService
   public class JAXServiceImpl implements JAXService {
   
       @Override
       public @WebResult(name="news")String sayHello(@WebParam(name="name") String name) {
           return name +"   hello!";
       }

   4.配置spirng配置文件,发布webService  jaxws:server 标签中的address 中的路径 就是访问webService的路径  实际路径是http://localhost:8080/ws/Users?wsdl(ws是项目名)

   <?xml version="1.0" encoding="UTF-8"?>
   
   <beans xmlns="http://www.springframework.org/schema/beans"
           xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
            xmlns:jaxws="http://cxf.apache.org/jaxws"
           xsi:schemaLocation="
               http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
               http://cxf.apache.org/jaxws http://cxf.apache.org/schemas/jaxws.xsd"
               >
   
           <!-- 发布的webService类 -->    
           <bean id="userServiceBean" class="cn.com.lrl.service.impl.JAXServiceImpl"/>
           
           <!-- 注意下面的address，这里的address的名称就是访问的WebService的name -->
           <jaxws:server id="userService" serviceClass="cn.com.lrl.service.JAXService" address="/Users">
               <jaxws:serviceBean>
                   <!-- 要暴露的 bean 的引用 -->
                   <ref bean="userServiceBean"/>
               </jaxws:serviceBean>
               <!-- 添加请求日志 -->
               <jaxws:inInterceptors> 
                   <bean class="org.apache.cxf.interceptor.LoggingInInterceptor"/> 
               </jaxws:inInterceptors> 
                  <!-- 添加响应 日志 -->
               <jaxws:outInterceptors> 
                   <bean class="org.apache.cxf.interceptor.LoggingOutInterceptor"/> 
                  </jaxws:outInterceptors> 
           </jaxws:server>
   </beans>

   5.启动tomcat发布webService 访问你的webService  如果是这样就代表成功了6.通过wsimport解析wsdl文件

　　

　　7.将生成的代码复制到要调用webService的项目

　　8.测试接口是否可以使用

public class Test {
    public static void main(String[] args) {
        JAXServiceService jaxServiceService =new JAXServiceService();
        JAXService jaxService=jaxServiceService.getJAXServicePort();
        //调用方法输出
        System.out.println(jaxService.sayHello("lrl"));
    }
}

　　9.调用成功 控制台输出