再论整型

#include <stdio.h>
#include <stdlib.h>

int main()
{
	unsigned long long un_var_long = 0;
	long long var_long = 0;
	unsigned int data_un = 0x8000;
	int data_si = 0x8000|0xffff0000;
	//int data_si = 0x7FFF;
	printf("data_si = %d
",data_si);
	printf("data_un = %u
",data_un);

	var_long = (long long)data_si *762962736 / 100000000;
	printf("var_long = %lld
",var_long);

	un_var_long = (unsigned long long)(0x10000 - data_un)*762962736 / 100000000;
	printf("un_var_long = %lld
",un_var_long);

	int sian_ddd = -124;
	printf("sian_ddd = %x
",sian_ddd);

	var_long = -12399999999456;
	printf("var_long = %lx
",var_long);
	//截断后，依然保留了符号
	sian_ddd = (int)var_long;
	printf("sian_ddd = %x
",sian_ddd);

	printf("long long = %x
",sizeof(long long));

	sian_ddd = 0x80000000;
	printf("sian_ddd--  = %d
",sian_ddd);
	sian_ddd = 0x7fffffff;
	printf("sian_ddd++  = %d
",sian_ddd);

	sian_ddd = 0xE667A220;
	printf("sian_ddd e6 = %d
",sian_ddd);
    printf("Hello world!
");
    return 0;
}

内存截图：只运行到sian_ddd = 0x80000000;之前的情况下。后续情况自行推导。

0x61fe04: 20 a2 67 e6 = -429415904
0x61fe08: 00 80 ff ff = -32768
0x61fe0c: 00 80 00 00 = 0x8000
0x61fe10: 20 a2 67 e6 b8 f4 ff ff = -12399999999456
0x61fe18: 97 d0 03 00 00 00 00 00 = 250007

变量信息

小结：

long long 转换为int类型是直接截断的，因此不确保int的符号位，因此需要特别注意,测试环境是gcc，x86的架构，因此是小端模式。
内存的信息都是0101，但是编译器怎么来解析一个数据，就根据定义的类型：类型大小，整型，浮点，有符号、无符号。而且是根据补码来解析的