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  • 【模板】高精度计算

    最基础的高精度,用$struct$封装后更易于使用。

    【CODE】

    #include<iostream>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<string>
    #include<cmath>
    #include<algorithm>
    using namespace std;
     
    const int MAXN = 410;
     
    struct bign{
        int len, s[MAXN];
        bign(){
            memset(s, 0, sizeof s);
            len = 1;
        }
        bign(int num){
            *this = num;  //=已重载
        }
        bign(const char *num){
            *this = num; //=已重载
        }
        bign operator = (const int num) {
            char t[MAXN];
            sprintf(t, "%d", num);
            *this = t;   //=此处已重载
            return *this;
        }
        bign operator = (const char *num){
            for(int i = 0; num[i] == '0'; num++); //去除前导0
            len = strlen(num);
            for(int i = 0; i < len; i++) s[i] = num[len - i - 1] - '0';
            //反转
            return *this;
        }
        bign operator + (const bign &b){
            bign c;
            c.len = 0;
            for(int i = 0, g = 0; g || i < max(len, b.len); i++){
                int x = g;
                if(i < len) x += s[i];
                if(i < b.len) x += b.s[i];
                c.s[c.len++] = x % 10;
                g = x / 10;    //g为每次加完的进位
            }
            return c;
        }
        bign operator += (const bign &b) {
            *this = *this + b;
            return *this;
        }
        void clean(){
            while(len > 1 && !s[len - 1]) len--;  //删除前导0
        }
        bign operator * (const bign &b) {
            bign c;
            c.len = len + b.len;  //最多的位数为两乘数位数之和
            for(int i = 0; i < len; i++)
                for(int j = 0; j < b.len; j++)
                    c.s[i + j] += s[i] * b.s[j];
            for(int i = 0; i < c.len; i++){
                c.s[i + 1] = c.s[i] / 10;
                c.s[i] %= 10;
            }
            c.clean();
            return c;
        }
        bign operator *= (const bign &b) {
            *this = *this * b;
            return *this;
        }
        bign operator - (const bign &b) {
            bign c;
            c.len = 0;
            for(int i = 0, g = 0; i < len; i++){
                int x = s[i] - g;  //g为借位
                if(i < b.len) x -= b.s[i];
                if(x >= 0) g = 0;
                else{
                    g = 1;
                    x += 10;
                }
                c.s[c.len++] = x;
            }
            c.clean();
            return c;
        }
        bign operator -= (const bign &b) {
            *this = *this - b;
            return *this;
        }
        bign operator / (const bign &b) {
            bign c, f = 0;
            for(int i = len - 1; i >= 0; i--){
                f = f * 10;
                f.s[0] = s[i];
                while(f >= b){
                    f -= b;
                    c.s[i]++;
                }
            }
            c.len = len;
            c.clean();
            return c;
        }
        bign operator /= (const bign &b) {
            *this = *this / b;
            return *this;
        }
        bign operator % (const bign &b) {
            bign r = *this / b;
            r = *this - r * b;
            return r;
        }
        bign operator %= (const bign &b){
            *this = *this % b;
            return *this;
        }
        bool operator < (const bign &b){
            if(len != b.len) return len < b.len;
            for(int i = len - 1; i >= 0; i--)
                if(s[i] != b.s[i]) return s[i] < b.s[i];
            return false;
        }
        bool operator > (const bign &b) {
            if(len != b.len) return len > b.len;
            for(int i = len - 1; i >= 0; i--)
                if(s[i] != b.s[i]) return s[i] > b.s[i];
            return false;
        }
        bool operator == (const bign &b) {
            return !(*this > b) && !(*this < b);
        }
        bool operator >= (const bign &b) {
            return *this > b || *this == b;
        }
        bool operator <= (const bign &b) {
            return *this < b || *this == b;
        }
        bool operator != (const bign &b) {
            return *this > b || *this < b;
        }
        string str() const{
            string ret = "";
            for(int i = len - 1; i >= 0; i--) ret += char(s[i] + '0');
            return ret;
        }
    };
     
    istream& operator >> (istream &in, bign &x){
        string s;
        in >> s;
        x = s.c_str();
        return in;
    }
     
    ostream& operator << (ostream &out, bign &x){
        out << x.str();
        return out;
    }
     
    int main(){
        bign a, b, c;
        cin>>a>>b;
        c = a + b;
        cout<<c;
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/CzYoL/p/7154246.html
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