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  • 洛谷 6道简单图论

    luogu 2002 消息扩散

    tarjan缩点:对原图进行tarjan缩点,对缩后的点连边,统计入度为0的点。

    luogu 1119 灾后重建

    Floyed:对于每个新加入的点,将其作为中转点,跑floyed。

    luogu 1186 玛丽卡

    最短路:类似次小生成树,求出最短路径后,将其路径上的每一条边删去,再求一遍。

    luogu 1462 通往奥格瑞玛的道路

    最短路+二分:二分最大值,将值大于二分值的都删去,看s和t是否连通。

    luogu 1613 跑路

    floyed+倍增:首先类似传递闭包或倍增求出两点间是否存在一条(2^k)的道路,若存在初始化dis[i][j] = 1,然后跑floyed。

    luogu 2700 逐个击破

    最大生成树:将边从大至小排序,将每个点看作一个集合,先将k个特殊点染色,然后从大至小枚举边,将边两边的点集合分情况合并:

    1. 一端染色,一端未染色:未染色端染上色,两集合合并。
    2. 两端都未染色: 两集合直接合并。
    3. 两端都染色: 加上该边的权值,合并集合。

    code

    luogu 2002

    #include<bits/stdc++.h>
    using namespace std;
    const int N = 1e5 + 50, M = 5e5 + 50;
    int n, m, low[N], dfn[N], clk, sccno[N], sccnum[N], sccCnt, ans, outdeg[N], indeg[N], from[N];
    vector<int> G[N];
    stack<int> S;
    
    inline void dfs(int u){
        dfn[u] = low[u] = ++clk;
        S.push(u);
    
        for(int e = G[u].size() - 1; e >= 0; e--){
            int v = G[u][e];
            if(!dfn[v]){
                dfs(v);
                low[u] = min(low[u], low[v]);
            }
            else if(!sccno[v]) low[u] = min(low[u], dfn[v]);
        }
        if(low[u] == dfn[u]){
            int x; sccCnt++;
            for(;;){
                x = S.top(); S.pop();
                sccno[x] = sccCnt;
                sccnum[sccCnt]++;
                if(x == u) return;
            }
        }
    }
    
    int main(){
        scanf("%d%d", &n, &m);
        for(int i = 1; i<= m; i++){
            int x, y; scanf("%d%d", &x, &y);
            if(x != y) G[x].push_back(y);
        }
        for(int i = 1; i <= n; i++)
            if(!dfn[i]) dfs(i);
    //    for(int i = 1; i <= n; i++) cout<<sccno[i]<<" "<<endl;
        for(int i = 1; i <= n; i++){
            for(int e = G[i].size() - 1; e >= 0; e--){
                int v = G[i][e];
                if(sccno[i] != sccno[v])
                    outdeg[sccno[i]]++, indeg[sccno[v]]++;
            }
        }
        for(int i = 1; i <= sccCnt; i++){
            if(!indeg[i] && !outdeg[i]) ans++;
            else if(!indeg[i]) ans ++;
        }
        printf("%d", ans);
        return 0;
    }
    

    luogu 1119

    #include<bits/stdc++.h>
    using namespace std;
    const int N = 220, OO = 0x3f3f3f3f;
    int n, m;
    int f[N][N], q;
    vector<int> h[1000000];
    bool vst[N];
    
    int main(){
        scanf("%d%d", &n, &m);
        for(int i = 1 ; i <= n; i++){
            int x; scanf("%d", &x);
            h[x].push_back(i);
        }
    
        memset(f, OO, sizeof f);
        for(int i = 1; i <= n; i++) f[i][i] = 0;
    
        for(int i = 1; i <= m; i++){
            int u, v, w; scanf("%d%d%d", &u, &v, &w);
            u++, v++;
            f[u][v] = f[v][u] = min(f[u][v], w);
        }
    
    
        scanf("%d", &q);
        int now = -1;
        for(int i = 1; i <= q; i++){
            int x, y, t; scanf("%d%d%d", &x, &y, &t);
            x++, y++;
            while(now < t){
                now++;
                for(int j = 0; j < h[now].size(); j++){
                    int u = h[now][j];
    //                cout<<now<<" "<<u<<endl;
                    vst[u] = true;
                    for(int k = 1; k <= n; k++)
                        for(int l = 1; l <= n; l++)
                            f[k][l] = min(f[k][l], f[k][u] + f[u][l]);
                }
            }
            printf("%d
    ", (f[x][y] < OO && vst[x] && vst[y]) ? f[x][y] : -1);
        }
        return 0;
    }
    

    luogu 1186

    #include<bits/stdc++.h>
    using namespace std;
    const int N = 1005, M = 1e6 + 5, OO = 0x3f3f3f3f;
    int n, ans, tmp, m;
    vector<pair<int, int> > G[N];
    vector<pair<int, int> > route;
    pair<int, int> from[N];
    int dis[N];
    #define mp make_pair
    priority_queue<pair<int, int>, vector<pair<int, int> >, greater<pair<int, int> > > que;
    
    inline void dj(int s, int t, int f, int a, int b){
        while(!que.empty()) que.pop();
        memset(dis, OO, sizeof dis);
        dis[s] = 0;
        que.push(mp(0, s));
        while(!que.empty()){
            pair<int, int> tt = que.top(); que.pop();
            int u = tt.second, dist = tt.first;
    //        cout<<u<<"->";
            if(u == t) break;
            for(int e = G[u].size() - 1; e >= 0; e--){
                int v = G[u][e].first;
                int len = G[u][e].second;
                if(f == 1 && ((u == a && v == b)|| (u == b && v == a))) continue;
    //            cout<<v<<" !!";
                if(dis[v] > dis[u] + len){
                    from[v] = mp(u, len);
                    dis[v] = dis[u] + len;
                    que.push(mp(dis[v], v));
                }
            }
    //        cout<<endl;
        }
    }
    
    int main(){
        scanf("%d%d", &n, &m);
        for(int i = 1; i <= m; i++){
            int a, b, c; scanf("%d%d%d", &a ,&b, &c);
            G[a].push_back(mp(b, c));
            G[b].push_back(mp(a, c));
        }
        dj(1, n, 0, 0, 0);
        ans = tmp = dis[n];
    //    cout<<dis[n]<<endl;
        int now = n;
        route.push_back(mp(now, 0));
        while(from[now].first) route.push_back(from[now]), now = from[now].first;
    //    for(int i = 0; i <= route.size() - 1; i++) cout<<route[i].first<<" "<<route[i].second<<endl;
        for(int i = 0; i < route.size() - 1; i++){
            int u = route[i].first, v = route[i + 1].first;
            dj(1, n, 1, u, v);
    //        cout<<u<<" "<<v<<" "<<dis[v]<<endl;
            ans = max(ans, dis[n]);
        }
        printf("%d", ans);
    }
    

    luogu 1462

    #include<bits/stdc++.h>
    using namespace std;
    const int N = 10005, M = 1e6 + 5;
    const long long OO = 2e18;
    int n, m, b;
    long long maxx = -OO, minn = OO, f[N];
    vector<pair<int, long long> > G[N];
    long long dis[N];
    #define mp make_pair
    priority_queue<pair<long long, int>, vector<pair<long long, int> >, greater<pair<long long, int> > > que;
    
    inline bool check(long long mid){
        if(f[1] > mid) return false;
        while(!que.empty()) que.pop();
        for(int i = 0; i <= n; i++) dis[i] = OO;
        dis[1] = 0;
        que.push(mp(0, 1));
        while(!que.empty()){
            pair<long long, int> t = que.top(); que.pop();
            if(t.second == n) return t.first <= b;
            int u = t.second;
            for(int e = G[u].size() - 1; e >= 0; e--){
                int v = G[u][e].first, len = G[u][e].second;
                if(f[v] > mid) continue;
                if(dis[v] > dis[u] + len){
                    dis[v] = dis[u] + len;
                    que.push(mp(dis[v], v));
                }
            }
        }
        return false;
    }
    
    int main(){
        scanf("%d%d%d", &n, &m, &b);
        for(int i = 1; i <= n; i++) scanf("%d", &f[i]), maxx = max(maxx, f[i]), minn = min(minn, f[i]);
        for(int i = 1; i <= m; i++){
            int x, y, c; scanf("%d%d%d", &x, &y, &c);
            G[x].push_back(mp(y, c)), G[y].push_back(mp(x, c));
        }
        long long l = minn, r = maxx, ans = -1;
        while(l <= r){
            long long mid = l + r >> 1;
            if(check(mid)) r = mid - 1, ans = mid;
            else l = mid + 1;
        }
        if(ans == -1) printf("AFK");
        else printf("%lld", ans);
        return 0;
    }
    

    luogu1613

    #include<bits/stdc++.h>
    using namespace std;
    const int N = 55, OO = 0x3f3f3f3f;
    int n, dis[N][N], m;
    bool f[N][N][35];
    
    int main(){
        scanf("%d%d", &n, &m);
        for(int i = 1; i <= m; i++){
            int x, y; scanf("%d%d", &x, &y);
            f[x][y][0] = true;
        }
        memset(dis, OO, sizeof dis);
        for(int l = 0; l <= 31; l++)
            for(int k = 1; k <= n; k++)
                for(int i = 1; i <= n; i++)
                    for(int j = 1; j <= n; j++){
                            if(l) f[i][j][l]= f[i][j][l] || (f[i][k][l - 1] && f[k][j][l - 1]);
                            if(f[i][j][l]) dis[i][j] = 1;
                        }
    //	for(int i = 1; i <= n; i++)
    //			for(int j = 1; j <= n; j++)
    //				for(int l = 1; l <= 5; l++)
    //					cout<<i<<" "<<j<<" "<<l<<" "<<f[i][j][l]<<endl;
    //	for(int i = 1; i <= n; i++)
    //		for(int j = 1; j <= n; j++)
    //			cout<<i<<" "<<j<<" "<<dis[i][j]<<endl;
        for(int k = 1; k <= n; k++)
            for(int i = 1; i <= n; i++)
                for(int j = 1; j <= n; j++)
                    dis[i][j] = min(dis[i][j], dis[i][k] + dis[k][j]);
        printf("%d", dis[1][n]);
        return 0;
    }
    

    luogu2700

    #include<bits/stdc++.h>
    using namespace std;
    const int N = 1e5+50;
    int n, k, anc[N];
    long long ans;
    bool mark[N];
    struct node{
        int x, y, c;
        inline bool operator < (const node &b) const{
            return c > b.c;
        }
    }edge[N];
    
    inline int getAnc(int x){
        return x == anc[x] ? x : (anc[x] = getAnc(anc[x]));
    }
    
    int main(){
        scanf("%d%d", &n, &k);
        for(int i = 1; i <= n; i++) anc[i] = i;
        for(int i = 1; i <= k; i++){
            int x; scanf("%d", &x);
            x++;
            mark[x] = true;
        }
        for(int i = 1; i < n; i++){
            int x, y, c; 
            scanf("%d%d%d", &x, &y, &c);
            x++, y++;
            edge[i] = (node){x, y, c};
        }
        sort(edge + 1, edge + n);
        for(int i = 1; i < n; i++){
            int x = edge[i].x, y = edge[i].y, c = edge[i].c;
            int fx = getAnc(x), fy = getAnc(y);
            if(fx != fy){
                if(mark[fx] && !mark[fy]){
                    mark[fy] = true;
                    anc[fx] = fy;
                }
                else if(!mark[fx] && mark[fy])
                    anc[fx] = fy;
                else if(mark[fx] && mark[fy]){
                    anc[fx] = fy;
                    ans += 1ll*c;
                }
                else if(!mark[fx] && !mark[fy])
                    anc[fx] = fy;
            }
    //		cout<<x<<" "<<y<<" "<<c<<" "<<ans<<endl;
        }
        printf("%lld", ans);
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/CzYoL/p/7767442.html
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