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  • Maximum Flow

      Here, I would like to use Ford-Fulkerson Method to determine the Maximum Flow of a given directed graph in the USACO training problem Drainage Ditches:

     1 import java.util.*;
     2 import java.io.*;
     3 
     4 public class ditch {
     5     public static final int INF = (1<<30);
     6     public static Scanner in;
     7     public static PrintWriter out;
     8     public static int num;        // number of vertices
     9     public static int[][] adjMat;    // residual matrix
    10     public static int[] path;        // record of augmented path
    11     public static int len;        // length of augmented path
    12     
    13     public static int maxFlow() {
    14         // Implementation of the Ford-Fulkerson Method
    15         int val = 0;
    16         while (genAugPath()) {
    17             // Whenever an augmented path is discovered
    18             //        the capacity of it will be added to the flow
    19             int min = INF;
    20             for (int i=0;i<len-1;i++) {
    21                 // Determine the capacity of the path
    22                 if (adjMat[path[i+1]][path[i]]<min)
    23                     min = adjMat[path[i+1]][path[i]];
    24             }
    25             for (int i=0;i<len-1;i++) {
    26                 // Modify the residual matrix
    27                 adjMat[path[i+1]][path[i]]-=min;
    28                 adjMat[path[i]][path[i+1]]+=min;
    29             }
    30             val += min;
    31         }
    32         return val;
    33     }
    34     public static boolean genAugPath() {
    35         // Breadth-First Search for an augmented path
    36         //        return whether a path has been found
    37         boolean[] vis = new boolean[num];
    38         Queue<Integer> q= new LinkedList<Integer>();
    39         int[] prev = new int[num];
    40         vis[0] = true;
    41         q.add(new Integer(0));
    42         prev[0] = -1;
    43         while (!q.isEmpty()){
    44             int k = q.poll().intValue();
    45             for (int i=1;i<num-1;i++) {
    46                 if (!vis[i]&&adjMat[k][i]>0) {
    47                     vis[i] = true;
    48                     q.add(new Integer(i));
    49                     prev[i] = k;
    50                 }
    51             }
    52             if (adjMat[k][num-1]>0) {
    53                 // When destination is reached,
    54                 //        an augmented path is found
    55                 len = 0;
    56                 path[len++] = num-1;
    57                 int idx = k;
    58                 while (idx>=0) {
    59                     path[len++] = idx;
    60                     idx = prev[idx];
    61                 }
    62                 return true;
    63             }
    64         }
    65         return false;
    66     }
    67     public static void main(String[] args) throws IOException{
    68         in = new Scanner(new FileReader("ditch.in"));
    69         int n = in.nextInt();
    70         num = in.nextInt();
    71         adjMat = new int[num][num];
    72         for (int i=0;i<n;i++) {
    73             adjMat[in.nextInt()-1][in.nextInt()-1] += in.nextInt();
    74         }
    75         in.close();
    76         out = new PrintWriter(new FileWriter("ditch.out"));
    77         path = new int[num];
    78         out.println(maxFlow());
    79         out.close();
    80     }
    81 }
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  • 原文地址:https://www.cnblogs.com/DevinZ/p/4411437.html
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