用keras实现lstm 利用Keras下的LSTM进行情感分析

1    I either LOVE Brokeback Mountain or think it’s great that homosexuality is becoming more acceptable!:
1    Anyway, thats why I love ” Brokeback Mountain.
1    Brokeback mountain was beautiful…
0    da vinci code was a terrible movie.
0    Then again, the Da Vinci code is super shitty movie, and it made like 700 million.
0    The Da Vinci Code comes out tomorrow, which sucks.
其中的每个句子都有个标签 1 或 0， 用来代表积极或消极。

    先把用到的包一次性全部导入
"language-python hljs">from keras.layers.core import Activation, Dense
from keras.layers.embeddings import Embedding
from keras.layers.recurrent import LSTM
from keras.models import Sequential
from keras.preprocessing import sequence
from sklearn.model_selection import train_test_split
import nltk #用来分词
import collections #用来统计词频
import numpy as np

     在开始前，先对所用数据做个初步探索。特别地，我们需要知道数据中有多少个不同的单词，每句话由多少个单词组成。
"language-pyhon hljs livecodeserver">maxlen = 0 #句子最大长度
word_freqs = collections.Counter() #词频
num_recs = 0 # 样本数
with open('./train.txt','r+') as f:
for line in f:
label, sentence = line.strip().split(" ")
words = nltk.word_tokenize(sentence.lower())
if len(words) > maxlen:
maxlen = len(words)
for word in words:
word_freqs[word] += 1
num_recs += 1
print('max_len ',maxlen)
print('nb_words ', len(word_freqs))

     max_len 42
     nb_words 2324
      可见一共有 2324 个不同的单词，包括标点符号。每句话最多包含 42 个单词。
      根据不同单词的个数 (nb_words)，我们可以把词汇表的大小设为一个定值，并且对于不在词汇表里的单词，把它们用伪单词 UNK 代替。 根据句子的最大长度 (max_lens)，我们可以统一句子的长度，把短句用 0 填充。
      依前所述，我们把 VOCABULARY_SIZE 设为 2002。包含训练数据中按词频从大到小排序后的前 2000 个单词，外加一个伪单词 UNK 和填充单词 0。 最大句子长度 MAX_SENTENCE_LENGTH 设为40。
MAX_FEATURES = 2000
MAX_SENTENCE_LENGTH = 40

      接下来建立两个 lookup tables，分别是 word2index 和 index2word，用于单词和数字转换。
"language-python hljs">vocab_size = min(MAX_FEATURES, len(word_freqs)) + 2
word2index = {x[0]: i+2 for i, x in enumerate(word_freqs.most_common(MAX_FEATURES))}
word2index["PAD"] = 0
word2index["UNK"] = 1
index2word = {v:k for k, v in word2index.items()}

      下面就是根据 lookup table 把句子转换成数字序列了，并把长度统一到 MAX_SENTENCE_LENGTH， 不够的填 0 ， 多出的截掉。
"language-python hljs">X = np.empty(num_recs,dtype=list)
y = np.zeros(num_recs)
i=0
with open('./train.txt','r+') as f:
for line in f:
label, sentence = line.strip().split(" ")
words = nltk.word_tokenize(sentence.lower())
seqs = []
for word in words:
if word in word2index:
seqs.append(word2index[word])
else:
seqs.append(word2index["UNK"])
X[i] = seqs
y[i] = int(label)
i += 1
X = sequence.pad_sequences(X, maxlen=MAX_SENTENCE_LENGTH)

      最后是划分数据，80% 作为训练数据，20% 作为测试数据。
"language-python hljs">Xtrain, Xtest, ytrain, ytest = train_test_split(X, y, test_size=0.2, random_state=42)

      数据准备好后，就可以上模型了。这里损失函数用 binary_crossentropy， 优化方法用 adam。 至于 EMBEDDING_SIZE , HIDDEN_LAYER_SIZE , 以及训练时用到的BATCH_SIZE 和 NUM_EPOCHS 这些超参数，就凭经验多跑几次调优了。
EMBEDDING_SIZE = 128
HIDDEN_LAYER_SIZE = 64
model = Sequential()
model.add(Embedding(vocab_size, EMBEDDING_SIZE,input_length=MAX_SENTENCE_LENGTH))
model.add(LSTM(HIDDEN_LAYER_SIZE, dropout=0.2, recurrent_dropout=0.2))
model.add(Dense(1))
model.add(Activation("sigmoid"))
pile(loss="binary_crossentropy", optimizer="adam",metrics=["accuracy"])

      网络构建好后就是上数据训练了。用 10 个 epochs 和 batch_size 取 32 来训练这个网络。在每个 epoch， 我们用测试集当作验证集。
BATCH_SIZE = 32
NUM_EPOCHS = 10
model.fit(Xtrain, ytrain, batch_size=BATCH_SIZE, epochs=NUM_EPOCHS,validation_data=(Xtest, ytest))

      Train on 5668 samples, validate on 1418 samples
      Epoch 1/10
      5668/5668 [==============================] - 12s - loss: 0.2464 - acc: 0.8897 - val_loss: 0.0672 - val_acc: 0.9697
      Epoch 2/10
      5668/5668 [==============================] - 11s - loss: 0.0290 - acc: 0.9896 - val_loss: 0.0407 - val_acc: 0.9838
      Epoch 3/10
      5668/5668 [==============================] - 11s - loss: 0.0078 - acc: 0.9975 - val_loss: 0.0506 - val_acc: 0.9866
      Epoch 4/10
      5668/5668 [==============================] - 11s - loss: 0.0084 - acc: 0.9970 - val_loss: 0.0772 - val_acc: 0.9732
      Epoch 5/10
      5668/5668 [==============================] - 11s - loss: 0.0046 - acc: 0.9989 - val_loss: 0.0415 - val_acc: 0.9880
      Epoch 6/10
      5668/5668 [==============================] - 11s - loss: 0.0012 - acc: 0.9998 - val_loss: 0.0401 - val_acc: 0.9901
      Epoch 7/10
      5668/5668 [==============================] - 11s - loss: 0.0020 - acc: 0.9996 - val_loss: 0.0406 - val_acc: 0.9894
      Epoch 8/10
      5668/5668 [==============================] - 11s - loss: 7.7990e-04 - acc: 0.9998 - val_loss: 0.0444 - val_acc: 0.9887
      Epoch 9/10
      5668/5668 [==============================] - 11s - loss: 5.3168e-04 - acc: 0.9998 - val_loss: 0.0550 - val_acc: 0.9908
      Epoch 10/10
      5668/5668 [==============================] - 11s - loss: 7.8728e-04 - acc: 0.9996 - val_loss: 0.0523 - val_acc: 0.9901

      可以看到，经过了 10 个epoch 后，在验证集上的正确率已经达到了 99%。

      我们用已经训练好的 LSTM 去预测已经划分好的测试集的数据，查看其效果。选了 5 个句子的预测结果，并打印出了原句。
"language-python hljs">score, acc = model.evaluate(Xtest, ytest, batch_size=BATCH_SIZE)
print(" Test score: %.3f, accuracy: %.3f" % (score, acc))
print('{} {} {}'.format('预测','真实','句子'))
for i in range(5):
idx = np.random.randint(len(Xtest))
xtest = Xtest[idx].reshape(1,40)
ylabel = ytest[idx]
ypred = model.predict(xtest)[0][0]
sent = " ".join([index2word[x] for x in xtest[0] if x != 0])
print(' {} {} {}'.format(int(round(ypred)), int(ylabel), sent))

      Test score: 0.052, accuracy: 0.990
      预测 真实 句子
       0       0      oh , and brokeback mountain is a terrible movie …
       1       1      the last stand and mission impossible 3 both were awesome movies .
       1       1      i love harry potter .
       1       1      mission impossible 2 rocks ! ! … .
       1       1      harry potter is awesome i do n’t care if anyone says differently ! ..

      可见在测试集上的正确率已达 99%.

      我们可以自己输入一些话，让网络预测我们的情感态度。假如我们输入 I love reading. 和 You are so boring. 两句话，看看训练好的网络能否预测出正确的情感。
"language-python hljs">INPUT_SENTENCES = ['I love reading.','You are so boring.']
XX = np.empty(len(INPUT_SENTENCES),dtype=list)
i=0
for sentence in INPUT_SENTENCES:
words = nltk.word_tokenize(sentence.lower())
seq = []
for word in words:
if word in word2index:
seq.append(word2index[word])
else:
seq.append(word2index['UNK'])
XX[i] = seq
i+=1
XX = sequence.pad_sequences(XX, maxlen=MAX_SENTENCE_LENGTH)
labels = [int(round(x[0])) for x in model.predict(XX) ]
label2word = {1:'积极', 0:'消极'}
for i in range(len(INPUT_SENTENCES)):
print('{} {}'.format(label2word[labels[i]], INPUT_SENTENCES[i]))

      积极    I love reading.
      消极    You are so boring.

  Yes ，预测正确。

     全部
# -*- coding: gbk -*-
from keras.layers.core import Activation, Dense
from keras.layers.embeddings import Embedding
from keras.layers.recurrent import LSTM
from keras.models import Sequential
from keras.preprocessing import sequence
from sklearn.model_selection import train_test_split
import collections
import nltk
import numpy as np
## EDA
maxlen = 0
word_freqs = collections.Counter()
num_recs = 0
with open('./train.txt','r+') as f:
for line in f:
label, sentence = line.strip().split(" ")
words = nltk.word_tokenize(sentence.lower())
if len(words) > maxlen:
maxlen = len(words)
for word in words:
word_freqs[word] += 1
num_recs += 1
print('max_len ',maxlen)
print('nb_words ', len(word_freqs))
## 准备数据
MAX_FEATURES = 2000
MAX_SENTENCE_LENGTH = 40
vocab_size = min(MAX_FEATURES, len(word_freqs)) + 2
word2index = {x[0]: i+2 for i, x in enumerate(word_freqs.most_common(MAX_FEATURES))}
word2index["PAD"] = 0
word2index["UNK"] = 1
index2word = {v:k for k, v in word2index.items()}
X = np.empty(num_recs,dtype=list)
y = np.zeros(num_recs)
i=0
with open('./train.txt','r+') as f:
for line in f:
label, sentence = line.strip().split(" ")
words = nltk.word_tokenize(sentence.lower())
seqs = []
for word in words:
if word in word2index:
seqs.append(word2index[word])
else:
seqs.append(word2index["UNK"])
X[i] = seqs
y[i] = int(label)
i += 1
X = sequence.pad_sequences(X, maxlen=MAX_SENTENCE_LENGTH)
## 数据划分
Xtrain, Xtest, ytrain, ytest = train_test_split(X, y, test_size=0.2, random_state=42)
## 网络构建
EMBEDDING_SIZE = 128
HIDDEN_LAYER_SIZE = 64
BATCH_SIZE = 32
NUM_EPOCHS = 10
model = Sequential()
model.add(Embedding(vocab_size, EMBEDDING_SIZE,input_length=MAX_SENTENCE_LENGTH))
model.add(LSTM(HIDDEN_LAYER_SIZE, dropout=0.2, recurrent_dropout=0.2))
model.add(Dense(1))
model.add(Activation("sigmoid"))
pile(loss="binary_crossentropy", optimizer="adam",metrics=["accuracy"])
## 网络训练
model.fit(Xtrain, ytrain, batch_size=BATCH_SIZE, epochs=NUM_EPOCHS,validation_data=(Xtest, ytest))
## 预测
score, acc = model.evaluate(Xtest, ytest, batch_size=BATCH_SIZE)
print(" Test score: %.3f, accuracy: %.3f" % (score, acc))
print('{} {} {}'.format('预测','真实','句子'))
for i in range(5):
idx = np.random.randint(len(Xtest))
xtest = Xtest[idx].reshape(1,40)
ylabel = ytest[idx]
ypred = model.predict(xtest)[0][0]
sent = " ".join([index2word[x] for x in xtest[0] if x != 0])
print(' {} {} {}'.format(int(round(ypred)), int(ylabel), sent))
##### 自己输入
INPUT_SENTENCES = ['I love reading.','You are so boring.']
XX = np.empty(len(INPUT_SENTENCES),dtype=list)
i=0
for sentence in INPUT_SENTENCES:
words = nltk.word_tokenize(sentence.lower())
seq = []
for word in words:
if word in word2index:
seq.append(word2index[word])
else:
seq.append(word2index['UNK'])
XX[i] = seq
i+=1
XX = sequence.pad_sequences(XX, maxlen=MAX_SENTENCE_LENGTH)
labels = [int(round(x[0])) for x in model.predict(XX) ]
label2word = {1:'积极', 0:'消极'}
for i in range(len(INPUT_SENTENCES)):
print('{} {}'.format(label2word[labels[i]], INPUT_SENTENCES[i]))