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  • 洛谷 2756 飞行员配对方案问题

    【题解】

      二分图最大匹配的模板题。

      

     1 #include<cstdio>
     2 #include<algorithm>
     3 #define N 1010
     4 #define rg register
     5 using namespace std;
     6 int n,m,tot,ans,T,last[N],v[N],from[N];
     7 struct edge{
     8     int to,pre;
     9 }e[N*N];
    10 struct rec{
    11     int x,y;
    12 }a[N];
    13 inline int read(){
    14     int k=0,f=1; char c=getchar();
    15     while(c<'0'||c>'9')c=='-'&&(f=-1),c=getchar();
    16     while('0'<=c&&c<='9')k=k*10+c-'0',c=getchar();
    17     return k*f;
    18 }
    19 int dfs(int x){
    20     for(rg int i=last[x],to;i;i=e[i].pre)if(v[to=e[i].to]!=T){
    21         v[to]=T;
    22         if(!from[to]||dfs(from[to])){
    23             from[to]=x;
    24             return 1;
    25         }
    26     }
    27     return 0;
    28 }
    29 inline bool cmp(rec a,rec b){return a.x<b.x;}
    30 int main(){
    31     n=read(); m=read();
    32     while(1){
    33         int x=read(),y=read();
    34         if(x==-1&&y==-1) break;
    35         e[++tot]=(edge){y,last[x]}; last[x]=tot;
    36     }
    37     for(rg int i=1;i<=m;i++) ++T,ans+=dfs(i);
    38     if(ans){
    39         printf("%d
    ",ans); tot=0;
    40         for(rg int i=1;i<=m;i++) if(from[i]) a[++tot]=(rec){from[i],i};
    41         sort(a+1,a+1+tot,cmp);
    42         for(rg int i=1;i<=tot;i++) printf("%d %d
    ",a[i].x,a[i].y);
    43     }
    44     else puts("No solution");
    45     return 0;
    46 } 
    View Code
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  • 原文地址:https://www.cnblogs.com/DriverLao/p/8922078.html
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