牛客小白月赛1 D 多项式乘法 【循环】

题目链接

https://www.nowcoder.com/acm/contest/85/D

思路
因为数据范围较小 ，所以 可以直接 一个一个乘

AC代码

#include <cstdio>
#include <cstring>
#include <ctype.h>
#include <cstdlib>
#include <cmath>
#include <climits>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <deque>
#include <vector>
#include <queue>
#include <string>
#include <map>
#include <stack>
#include <set>
#include <numeric>
#include <sstream>
#include <iomanip>
#include <limits>

using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;

const double PI  = 3.14159265358979323846264338327;
const double E   = 2.718281828459;
const double eps = 1e-6;

const int INF    = 0x3f3f3f3f;
const int maxn   = 1e3 + 5;
const int MOD    = 1e9 + 7;

int ans[maxn];

struct Node
{
    int x, y;
}q[maxn];

int main()
{
    memset(q, 0, sizeof(q));
    memset(ans, 0, sizeof(ans));
    int n, m, num, count = 0;
    scanf("%d%d", &n, &m);
    for (int i = 0; i <= n; i++)
    {
        scanf("%d", &num);
        if (num)
        {
            q[count].x = num;
            q[count].y = i;
            count++;
        }
    }
    for (int i = 0; i <= m; i++)
    {
        scanf("%d", &num);
        if (num)
        {
            for (int j = 0; j < count; j++)
                ans[i + q[j].y] += num * q[j].x;
        }
    }
    int len = n + m + 1;
    for (int i = 0; i < len; i++)
    {
        if (i)
            printf(" ");
        printf("%d", ans[i]);
    }
    printf("
");
}